2 cos(4x) – 4 x² – 2 lim - - sin(6x) – x2 – 6x - - (Use calculator and write

Q: [In(x²)-ex cos(x-1).tan(Tx) 20. lim 2x2-x sin2(1-x) X-1

A:

Q: 9. Lim 6x - Sin 2x メ→0 2x +3sin 4X b. lim x²-1 1/2

A:

Q: 2. Find if possible: sin(nx) a) lim x-4 x2-16 b) lim x (sinx+(cosx)³) (x2+1)(x-3) c) lim,--o (cosx)

A: a) Given that limx→-4sin(πx)x2-16we have to find the limit of…

Q: Compute x-+xX lim X-700 It Ttx Sinx 2) Lim X-70 CUSX-1 X3-1 1L-X

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: Find the limit: x->0  2 sin2 3x / 3x2

A:

Q: 1-cos x 9. lim x00 x2

A:

Q: (2) 1: limx-1 sin(x3–1) x-1

A: limx→1 (2-1x)2sin(x3-1)x-1=limx→1 (2x-1x)2sin(x3-1)x-1=limx→1 4x2-4x+1x2sin(x3-1)x-1=limx→1…

Q: lim cos x+4e* is 5er

A:

Q: 1 2. lim cOs X -

A: The given function rewrite as

Q: 2 -x² + 2x – 7 lim sin 2x5 – x3 + 2x

A:

Q: -lim COS X tanx <-2メ X-8 2 lim 3 x→2 x42x +X-2 A

A:

Q: -1 sin (5x) lim

A: The given expression is limx→0sin-15xx the given expression is the indeterminate form 00 Apply L'…

Q: Q3) Find: (1) lim, 1+cos 2x (2) limx→-2- (x + 2) |4-x²| 2-x

A: Q3)1Here, we need to calculate the limit of ,limx→π21+cos2x4x-π2

Q: 1-cos 2x lim x→0 x2

A: “Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: Find the value of Tx³ + 2. lim [sin x3 + 1 -1 1 O O

A: Since you have asked multiple question, we will solve the first question for you. If youwant any…

Q: 2x -cos(2x)- 2x - (b) lim | x2

A:

Q: Compute 1) Lim X-3.9טTX 2) um X-71T sin x TT-X 3) um -X. X2-X-6

A: (1) The given expression of limit is

Q: tan (5x) x sin3 (2x) 2)- limx-o:

A: we have to evaluate the A=limx→0tan4(5x)xsin3(2x)

Q: In(cos ax) limx-0 ? In(cos bx)

A:

Q: 1 COS X 13. lim- ズ→0 14. lim e -3x+4 15. lim 4x+7 ー-00

A:

Q: 1-coskx 2. lim = 0. kx

A: We have to find the limit of the function (1-coskx)/kx when x tends to 0 .

Q: why is limx->0[x^4 * cos(2/3x)] not equal to zero? I thought that if I plug in zero to x^4 it makes…

A: Given that: limx→0x4.cos23x

Q: x- cosX X- COS X 4. lim,

A: Our Aim is to evaluate the limits given below:-limx→∞x-cos (x)x-(i)

Q: cos(7x) – 3 + b lim- x-0 e2x – bx – 1

A:

Q: tan(1 – x) limx→1 2 2x +x – 3,

A: Limit

Q: b) lim sin(x² – 4) х* -16 2х - 3 а) lim %3D V3x² +16 x->2 X->-0

A:

Q: Find values of a and b such that sin 3x + ax + bx³ lim = 0 x3

A:

Q: Evaluate: lim   (1−cos−1x)csch(1−x) x→1−

A: We have to find the limit.

Q: tan 2x lim 4.x4

A:

Q: x+1-cos²(x) 3sin(x) 7. Find lim

A:

Q: cos x-2sinx 1. limx-n 3cosx -2 limx-3 X-3 3x6-x*+2x-3 limy--o 4x5+2x3-5 iv. lim,→-1(x³ limy--1(x³ –…

A: [i]

Q: 2tan 'x -x (-) 2x – sin 'x 02. lim, -1

A: Given limx→02tan-1x-x2x-sin-1xTo evaluate the limit:

Q: (1) lim,-0 √x+9-3 X (2) lim-0 1–c05x x sinx (3) limx-1 x²+3x-4 x-1

A:

Q: Find x² lim x0 1 - cos x

A: Solved below...

Q: find lim x-> 0, cos (12x)-1 / 3x

A: Given,              limx→0cos 12x - 13x Move the term 1/3 outside of the limit because it is…

Q: 3 lim tan³ 2x x→0

A:

Q: 2. Evaluate cosxsin2x lim 1 – sinx

A: We need to find limx→π2cos x sin 2x1-sin x Now, put the limit in the function, that is put x=π2 .…

Q: In cos 2.x 4. Find lim -0 In cos 3x

A: limx→0ln (cos 2x)ln(cos 3x)Applying L'hospital rule:= limx→0ddxln(cos 2x)ddxln(cos 3x)= limx→0…

Q: Find lim sin (4 T x). I -3

A:

Q: 5 sin(6x) lim x→0 3x

A:

Q: х(4+sin 6x) 3. lim X→+0 х+1

A:

Q: 7x( cos (4x) – 1) Use l'Hôpital's Rule to evaluate lim sin (5x) – 5x

A:

Q: 2х а) lim -1-2x (sin 2x)+² - et b) lim -4x - cos x

A:

Q: limx¬1 x(1 – cos-) x→1

A:

Q: 2+ sec (3x) (с) lim я (6 tan (3x) —1

A: