Question
Asked Nov 7, 2019
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 Evaluate the integral by changing to cylindrical coordinates.

-2 r2 -y2
(r22/dz dy dx
-Jr2 +y2
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-2 r2 -y2 (r22/dz dy dx -Jr2 +y2

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Expert Answer

Step 1

Given triple integral as,

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-2-x1-y (x2 + y? }? dzdydx 2=1x? 1-

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Step 2

Where the limits are

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1 to x 1 x y = -i-x to y= -x z x2y to y 2-x2-y

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Step 3

Now change the coordinates to ...

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r rcos y rsin 0 z Z so, dzdydx rdzdedr

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Tagged in

Math

Calculus

Integration