General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter18: Thermodynamics And Equilibrium
Section18.6: Relating ?g° To The Equilibrium Constant
Problem 18.8E: Use the data from Table 18.2 to obtain the equilibrium constant Kp at 25C for the reaction...
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![Exercise
Calculate Kc or Kp for the following reactions with the given equilibrium concentrations.
2HI(g) H2(g) + 12(g)
at equilibrium, pH₂ = pl2 = 0.12649 atm pHI = 1.000atm
1.
k<p = (PH₂) (PI₁₂)
(PHI)
2.
3.
KC=
4.
3
[2.5x10-¹9][2.5x10"]
5.
6.
(0..12640) ?
(1.000)2
2NOCI(g) 2NO(g) + Cl2(g)
at equilibrium, [NO]=0.04M [C12] =0.02M [NOCI] = 0.348M
Sn(s) + 2Cl2(g) SnCl4(g)
at equilibrium, [SnCl4] = 0.378M [C1₂] = 1.34 x 10 M
378
1.34×104/2
[Sncla]
EC132
SnO2(s) + 2H2(g) Sn(s) + 2H₂O(g)
at equilibrium, [H₂O] = [H₂] = 0.10M
2010/600/
Fe(s) + 5 CO(g) Fe(CO)5(g)
at equilibrium, [CO] = 1.34 x 10 M [Fe(CO)5] = 2.5 M
ke = [fe(col_25 - 5.8×1.
[Co]}]
3Mg(OH)2(S) + 2NH3(g)
at equilibrium, pNH3 = 1.34 x 104 atm
Mg3N2(S) + H₂0 (1)
+
2 2.11 X 10](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3f4c86b2-1247-4388-bf18-f90827f5643c%2F3fe2b0c8-7957-490a-807f-9e67112d78e0%2Ffjrjdz9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Exercise
Calculate Kc or Kp for the following reactions with the given equilibrium concentrations.
2HI(g) H2(g) + 12(g)
at equilibrium, pH₂ = pl2 = 0.12649 atm pHI = 1.000atm
1.
k<p = (PH₂) (PI₁₂)
(PHI)
2.
3.
KC=
4.
3
[2.5x10-¹9][2.5x10"]
5.
6.
(0..12640) ?
(1.000)2
2NOCI(g) 2NO(g) + Cl2(g)
at equilibrium, [NO]=0.04M [C12] =0.02M [NOCI] = 0.348M
Sn(s) + 2Cl2(g) SnCl4(g)
at equilibrium, [SnCl4] = 0.378M [C1₂] = 1.34 x 10 M
378
1.34×104/2
[Sncla]
EC132
SnO2(s) + 2H2(g) Sn(s) + 2H₂O(g)
at equilibrium, [H₂O] = [H₂] = 0.10M
2010/600/
Fe(s) + 5 CO(g) Fe(CO)5(g)
at equilibrium, [CO] = 1.34 x 10 M [Fe(CO)5] = 2.5 M
ke = [fe(col_25 - 5.8×1.
[Co]}]
3Mg(OH)2(S) + 2NH3(g)
at equilibrium, pNH3 = 1.34 x 104 atm
Mg3N2(S) + H₂0 (1)
+
2 2.11 X 10
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