Question
Asked Nov 5, 2019
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2. A 0.600-kg particle has a speed of 2.00 m/s at point A and kinetic energy of 7.50 J at point B. What is (a) its kinetic energy at A? (b) its speed at B? (c) the total work done on the particle as it moves from A to B?

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Expert Answer

Step 1

Given:

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m 0.600kg 3 2.00т / s V КЕ, = 7.50J

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Step 2

Kinetic energy:

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KE =mV 2 here KE kinetic energy m =mass V= speed

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Step 3

 

Part(a):

Kinetic energy...

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KE, m -тV, 2 1 КЕ 2 (0.600) (2.0) KE 1.2J

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