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StatisticsQ&A Library2. A clinical trial is being conducted in order to determine the efficacy of a new drug used to treat Rheumatoid arthritis. The efficacy of the medication will not only be determined by the physical improvement of symptoms but also by using a blood test to examine the concentration C-reactive protein(an inflammatory marker) in an individual’s blood. If the researcher wants a margin of error for the level of C-reactive protein to be less than or equal to 3.0 mg/dL, and if the standard deviation for C-reactive protein concentrations among arthritis patients was previously documented at 8 mg/dL, how many patients should be recruited for each group in the study assuming a 95% confidence interval will be used to quantify the mean differences between the control group and the treatment group? Choose from the following. A)n for the treatment group = 112;n for the control group = 111 B)n for the treatment group = 56;n for the control group = 57 C)n for the treatment group = 56;n for the control group = 56 D)n for the treatment group = 112;n for the control group = 112Question

Asked Dec 5, 2019

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2. A clinical trial is being conducted in order to determine the efficacy of a new drug used to treat Rheumatoid arthritis. The efficacy of the medication will not only be determined by the physical improvement of symptoms but also by using a blood test to examine the concentration C-reactive protein

(an inflammatory marker) in an individual’s blood. If the researcher wants a margin of error for the level of C-reactive protein to be less than or equal to 3.0 mg/dL, and if the standard deviation for C-reactive protein concentrations among arthritis patients was previously documented at 8 mg/dL, how many patients should be recruited for each group in the study assuming a 95% confidence interval will be used to quantify the mean differences between the control group and the treatment group? Choose from the following.

A)

n for the treatment group = 112;

n for the control group = 111

B)n for the treatment group = 56;

n for the control group = 57

C)

n for the treatment group = 56;

n for the control group = 56

D)

n for the treatment group = 112;

n for the control group = 112

Step 1

Given that

Margin of error is 3.0 mg/dL

Standard deviati...

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