2. A curve is such that = 2(3x + 4)3/2 – 6x – 8. Given that the stationary point on the curve has coordinates (-1,5). Find the equation of the curve. dx (a) y = (3x + 4)5/2 – 3x² – 8x + (b) y = (3x + 4)8/2 – 3x² – 8x – (c) y =(3x + 4)$/2 – 3x² – 8x – (d) y =(3x + 4)/2 – 3x² – 8x – 15 15 4 (e) y = (3x + 4)5/2 – 3x² – 8x - 15

Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Conic Sections
Section8.2: More Parabolas And Some Circles
Problem 63.1PS
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2. A curve is such that = 2(3x + 4)3/2 – 6x – 8. Given that the stationary point on the curve has
coordinates (-1,5). Find the equation of the curve.
dx
(a) y = (3x + 4)5/2 – 3x² – 8x +
(b) y = (3x + 4)8/2 – 3x² – 8x –
(c) y =(3x + 4)$/2 – 3x² – 8x –
(d) y =(3x + 4)/2 – 3x² – 8x –
15
15
4
(e) y = (3x + 4)5/2 – 3x² – 8x -
15
Transcribed Image Text:2. A curve is such that = 2(3x + 4)3/2 – 6x – 8. Given that the stationary point on the curve has coordinates (-1,5). Find the equation of the curve. dx (a) y = (3x + 4)5/2 – 3x² – 8x + (b) y = (3x + 4)8/2 – 3x² – 8x – (c) y =(3x + 4)$/2 – 3x² – 8x – (d) y =(3x + 4)/2 – 3x² – 8x – 15 15 4 (e) y = (3x + 4)5/2 – 3x² – 8x - 15
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