Question

Asked Dec 9, 2019

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Please answer without software

Step 1

2.

You use z=(x-mu)/sigma twice and get two linear equations which you can then solve for *µ* and σ.

One equation: 0.2257 units of area between z and 0, so 0.5000 – 0.2257 = 0.2743 area to the left of z. Use a table of values or a stats calculator to find z= –0.6 approximately. Substitute z= –0.6 and x=100 into z=(x-mu)/sigma.

Second equation: area 0.4918 from mean (z=0) to 190. Area to left is 0.5+0.4918 = 0.9918 which gives a z value of z=2.4 approximately. Substitute z=2.4, x=190 into z=(x-mu)/sigma.

Two equations in two unknowns , use linear algebra to solve:

Step 2

The value of m...

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