2. Determine the intervals on which f (x)= is concave up and concave down. . x* +1 Then state the inflection points. state so. Round answers to 2 decimal places, if needed. If there or no intervals of concavity or no inflection points, then

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Chapter3: Functions
Section3.3: More On Functions; Piecewise-defined Functions
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2. Determine the intervals on which f (x)= is concave up and concave down. .
x* +1
Then
state the inflection points.
state so. Round answers to 2 decimal places, if needed.
If there or no intervals of concavity or no inflection points, then
Transcribed Image Text:2. Determine the intervals on which f (x)= is concave up and concave down. . x* +1 Then state the inflection points. state so. Round answers to 2 decimal places, if needed. If there or no intervals of concavity or no inflection points, then
Expert Solution
Step 1 Given

fx =xx2+1 

First find the inflection point of given function 

An inflection point is a point on the graph at which the second derivative changes sign.

If f''x >0 then fx concave upwards.

If f''x <0 then fx concave downwards.

Find derivative of fx  with respect to x .

ddxfx = ddxxx2+1

Apply the quotient rule 

fg'=f'g-g'fg2

fx =x, gx =x2+1

f'x =1, g'x =2x

Plug all this values in given formula 

ddxxx2+1 =1x2+1-2xxx2+12=x2+1-2x2x2+12f'(x)=1-x2x2+12

Find second derivative 

f''(x)=-2x-x2+3x2+13

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