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PhysicsQ&A Library2. In the figure an electron is shot with an initial speed of vo = 2.00x10° m/s, at an angle0,340° from an x-axis. It moves through a uniform electric field E=5.0 N/C, pointed inthe +y direction. A screen for detecting electrons is positioned parallel to the y-axis, at adistance x-3.00 m. What is the magnitude of the electron's velocity when it hits thescreen?%3DDetectinScreehQuestion

Asked Jan 29, 2020

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Question uploaded with figure...thanks

Step 1

**Given**

Initial velocity V_{o} =2.00 x 10^{6} m/s

Angle θ_{o} = 40^{o}

Electric field E = 5.0 N/C

Screen distance X = 3.00 m

**Known values**

Charge of electron q = 1.6 x10^{-19} C

Mass of electron m = 9.12 x 10^{-31} kg

Step 2

**Solution**

Resolving the initial velocity of the electron into X and Y components

Step 3

Since the field is acting only in y direction, there is no acceleration in x direction. So the final velocity in x dir...

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