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Asked Feb 8, 2020
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2. Let f(x) = 0.1(x³ – 3x2 – 9x). Then
%3D
f'(x) = 0.1(3x? – 6x – 9) = 0.3(x + 1)(x – 3)
%3D
f"(x) = 0.6(x – 1)
%3D
(a) Solutions to f'(x) = 0 are x =
(b) The function f is increasing on the interval(s)
%3D
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2. Let f(x) = 0.1(x³ – 3x2 – 9x). Then %3D f'(x) = 0.1(3x? – 6x – 9) = 0.3(x + 1)(x – 3) %3D f"(x) = 0.6(x – 1) %3D (a) Solutions to f'(x) = 0 are x = (b) The function f is increasing on the interval(s) %3D

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(c) The function f is concave down on the interval(s)
is an inflection point on the graph of f.
(d)
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(c) The function f is concave down on the interval(s) is an inflection point on the graph of f. (d)

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