2. The data below were obtained for a polymerization reaction at 350 K: [M] (kmol / m³) [1) (mol / m³) -d[M]/dt (mol/m³s) 9.04 0.235 0.193 8.63 0.206 0.170 7.19 0.255 0.165 6.13 0.228 0.129 4.96 0.313 0.122 4.75 0.192 0.0937 4.22 0.230 0.0867 Where [M] = monomer concentration and [1] = initiator concentration.
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- ANSWER ASAP At point B (35 wt% Ni, 1250ºC) on figure, What is the composition of solid and liquid components?Why is adsorption phenomenon always exothermic?What are the chemical potentials of Au and Ag at 500°C? Express you’re answer in eV per atom. 15 g of gold (Au) and 25 g of silver (Ag) are mixed to form a single-phase ideal solid solution. By how much will the free energy of the solution change at 500°C if one Au atom is added? Express your answer in eV per atom. Hint: You will need to find the specific heats of Au and Ag as functions of temperature to fix the free energies of the pure phases. In doing so, please pay attention to the units and cite the reference you pick the data from.
- 10.11/ A 1.5-kg specimen of a 90 wt% Pb-10 wt% Sn alloy is heated to 250°C (480°F), at which temperature it is entirely an a-phase solid solution . The alloy is to be melted to the extent that 50% of the speci- men is liquid, the remainder being the a phase. This may be accomplished either by heating the alloy or changing its composi- tion while holding the temperature con- stant. (a) To what temperature must the speci- men be heated? (b) How much tin must be added to the 1.5-kg specimen at 250°C to achieve this state? 10.15) A magnesium-lead alloy of mass 5.5 ka consists of a solid a phase that has a compo- sition that is just slightly below the solubility limit at 200°C (390°F). (a) What mass of lead is in the alloy? (b) If the alloy is heated to 350°C (660°F). how much more lead may be dissolved in the a phase without exceeding the solubility limit of this phase? 10.27 A hypothetical A-B alloy of composition 55 wt% B-45 wt% A at some temperature is found to consist of mass…Calculate the fraction condensed and the degree of polymerization at t = 5.00 h of a polymer formed by a stepwise process with kr = 1.39 dm3 mol−1 s−1 and an initial monomer concentration of 10.0 mmol dm−3.Determine the diffusion coefficient D for the diffusion of hydrogen into FCC iron at 800°C
- When factor (Q-S)/S is small , a crystalline solid is more likely.Given below (c): Standard gibb's free energies (∆Gf0 kJ mol-1 ): UO2 = -962.7 UO22+ = -953.5 U4+ = -579.1 Fe2+ = -78.9 Fe(OH)3 ferrihydrite = -692.07 Mn2+ = -288.1 MnO2 pyrolusite = -465.1 HS- = 12.1 H+ = 0 H2O = -237.1 S0 = 0 Given: U(VI) as uraninite; UO2 (where Mn2+ = reductant; MnO2 pyrolusite = product): ∆ Gr0 = -21.3 KJ/mol E0 (emf) = 0.110 V n = 2 F = 96.42 QUESTION: Calculate Eh equation below to calculate at different pH: – Eh = E0 + (RT/nF) * lnK For U(VI) as uraninite; UO2 (where HS- = reductant; S0 = product): UO22+ + Hs- ---- > UO2 + S + H+ [A] pH 3 [B] pH 7An experimental method of determining solubility parameters of polymers involves taking lightly crosslinked (network) samples of the polymers in question and immersing them in different solvents whose solubility parameters are known. Explain the rationale behind this method.
- How much energy must be removed from a 94.4 g sample of benzene (molar mass= 78.11 g/mol) at 322.0 k to solidify the sample and lower the temperature to 205.0 K? The following physical data may be useful.DHvap = 33.9 kJ/molDHfus = 9.8 kJ/molCliq = 1.73 J/g°CCgas = 1.06 J/g°CCsol = 1.51 J/g°CTmelting = 279.0 KTboiling = 353.0 KAn elastomer is a polymer that can stretch and contract. In a perfect elastomer the force opposing extension is proportional to the displacement x from the resting state of the elastomer, so |F| = kfx, where kf is a constant. But suppose that the restoring force weakens as the elastomer is stretched, and kf(x) = a − bx1/2. Evaluate the work done on extending the polymer from x = 0 to a final displacement x = l.Formula for work done in isobaric process(according to chemistry thermodynamics)