2. The slope of the melting curve of methane (CH4) is given by dP (0.08446 bar/K1.85). T0.85 dT (yes, the exponents are all correct!) from the triple point to arbitrary temperatures. Using the fact that the temperature and pressure of the triple point are 90.68 K and 0.1174 bars, calculate the melting pressure (in bars) of methane at 150 K. (Hint: You will need to integrate to obtain the correct pressure!)

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter9: Liquids And Solids
Section: Chapter Questions
Problem 13QAP
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help with question 2 please.

2. The slope of the melting curve of methane (CH4) is given by
dP
(0.08446 bar/K1.85). T0.85
%3D
dT
(yes, the exponents are all correct!) from the triple point to arbitrary temperatures. Using
the fact that the temperature and pressure of the triple point are 90.68 K and 0.1174 bars,
calculate the melting pressure (in bars) of methane at 150 K. (Hint: You will need to
integrate to obtain the correct pressure!)
3. The following data are available for the two "traditional" solid forms of carbon at 300 K,
Allotrope
AH combustion (kJ/mol)
S° (J/mol-K)
Density (g/cm³)
diamond
395.320
2.397
3.513
graphite
393.425
5.740
2.260
(a) What is the Gibbs free energy (in kJ/mol) of the transition from graphite to diamond at 1
bar and 300 K? In which direction is the process spontaneous?
(b) Estimate the pressure (in bars) at which the two allotropes would be in equilibrium at
300 K. To address this question, consider how the Gibbs energy changes with pressure at
a given Tusing = V. Assume that the densities of the two allotropes are
%3D
T.
independent of pressure (this is actually incorrect in real life!).
Transcribed Image Text:2. The slope of the melting curve of methane (CH4) is given by dP (0.08446 bar/K1.85). T0.85 %3D dT (yes, the exponents are all correct!) from the triple point to arbitrary temperatures. Using the fact that the temperature and pressure of the triple point are 90.68 K and 0.1174 bars, calculate the melting pressure (in bars) of methane at 150 K. (Hint: You will need to integrate to obtain the correct pressure!) 3. The following data are available for the two "traditional" solid forms of carbon at 300 K, Allotrope AH combustion (kJ/mol) S° (J/mol-K) Density (g/cm³) diamond 395.320 2.397 3.513 graphite 393.425 5.740 2.260 (a) What is the Gibbs free energy (in kJ/mol) of the transition from graphite to diamond at 1 bar and 300 K? In which direction is the process spontaneous? (b) Estimate the pressure (in bars) at which the two allotropes would be in equilibrium at 300 K. To address this question, consider how the Gibbs energy changes with pressure at a given Tusing = V. Assume that the densities of the two allotropes are %3D T. independent of pressure (this is actually incorrect in real life!).
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