Question

Asked Feb 28, 2019

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Step 1

The integrand can be decomposed partially.

Step 2

The values of *A, B, C and D *are obtained on comparing such that A=0, –2A+B=1, 2A-2B+C=0 and 2B+D=1. That is, the value of A is substituted in -2A+B=1 which gives B=1. Substituting both A and B in 2A-2B+C=0 gives C=2 and substituting B in 2B+D=1 gives –1. Thus, the partially decomposed integrand becomes

Step 3

Obtain the integral...

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