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Social Science21. c0phx x>0284CHAPTER 4Applications of Differentia37. h(t)= t3/4211/4- 2r1/438. g(x)= 439. F(x)= x4/5(x4)40. g(0)=4041. f(0)= 2 cos 0 sin 042. h(t) = 3t43. f(x)= xe244. f(x)= x45-46 A formula for the derivative of a functionHow many critical numbers does f have?1045. f'(x)= 5e0sinx-1 46. f'(x)147-62 Find the absolute maximum and absolutevalues of f on the given interval.12 + 4x - x, [0, 5]47. f(x)48. f(x) = 5 +54x - 2x3, [0, 4]49. f(x) 2x-3x2-12x + 1, [-2, 3]w50. f(x)= x- 6x2+ 5, [-3, 5]51. f(x) 3x-4x-12x2 + 1, [-2, 3131
I need help with question 39 in Section 4.1, page 284, of the James Stewart Calculus Eighth Edition textbook. I am trying to find the critical numbers for the function provided.
![21. c0phx x>0
284
CHAPTER 4
Applications of Differentia
37. h(t)= t3/4
211/4
- 2r1/4
38. g(x)= 4
39. F(x)= x4/5(x4)
40. g(0)=40
41. f(0)= 2 cos 0 sin 0
42. h(t) = 3t
43. f(x)= xe
2
44. f(x)= x
45-46 A formula for the derivative of a function
How many critical numbers does f have?
10
45. f'(x)= 5e0sinx-1 46. f'(x)
1
47-62 Find the absolute maximum and absolute
values of f on the given interval.
12 + 4x - x, [0, 5]
47. f(x)
48. f(x) = 5 +54x - 2x3, [0, 4]
49. f(x) 2x-3x2-12x + 1, [-2, 3]
w
50. f(x)= x- 6x2+ 5, [-3, 5]
51. f(x) 3x-4x-12x2 + 1, [-2, 31
31](https://prod-qna-question-images.s3.amazonaws.com/qna-images/question/9b9bfc7b-5e86-435c-b9dd-a07d54ff6a7e/73c5e290-8d32-4bb9-a910-4ac94a93a465/t4wl08f.jpeg)
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21. c0phx x>0 284 CHAPTER 4 Applications of Differentia 37. h(t)= t3/4 211/4 - 2r1/4 38. g(x)= 4 39. F(x)= x4/5(x4) 40. g(0)=40 41. f(0)= 2 cos 0 sin 0 42. h(t) = 3t 43. f(x)= xe 2 44. f(x)= x 45-46 A formula for the derivative of a function How many critical numbers does f have? 10 45. f'(x)= 5e0sinx-1 46. f'(x) 1 47-62 Find the absolute maximum and absolute values of f on the given interval. 12 + 4x - x, [0, 5] 47. f(x) 48. f(x) = 5 +54x - 2x3, [0, 4] 49. f(x) 2x-3x2-12x + 1, [-2, 3] w 50. f(x)= x- 6x2+ 5, [-3, 5] 51. f(x) 3x-4x-12x2 + 1, [-2, 31 31
Expert Answer
At first let us find the derivative of the function:
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F(x) x5 (x-4) Therefore 4 (x-4)+x32(x-4) F(x) 5 4(x-4)+10x (x-4) or, F(x) 5x3 Thus, F'(x) will be undefined at x = 0. 4
Now, let us find where F'(x) is undefined. A...
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