21.0 V, E2 15.0 V, and R = 17.0 .)In the figure below, find the following. (Let &1E128.0 Ω12.00R(a) the current in each resistorAI2 =AI3 =A(b) the power delivered to each resistorP1P2 =WP3W

(a)Apply Kirchhoff’s loop rule in the top loop (The loop that consist of the batteries and the…

Answered: 21.0 V, E2 15.0 V, and R = 17.0 .) In…

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter28: Current And Resistance

Section: Chapter Questions

Problem 67PQ

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A child's electronic toy is supplied by three 1.58-V alkaline cells having internal resistances of 0.0200 inseries with a 1.53-V carbon-zinc dry cell having a 0.100- internal resistance. The load resistance is 10.0 . (a) Draw a circuit diagram of the toy and itsbatteries, (b) What current flows? (c) How much power is supplied to the load? (d) What is the internal resistance of the dry cell if it goes bad, resulting in only 0.500 W being supplied to the load?
The power dissipated in a resistor is given by P = V2/R, which means power decreases if resistance increases. Yet this power is also given by P = I2R, which means power increases if resistance increases. Explain why there is no contradiction here.
Three 60.0-W, 120-V lightbulbs are connected across a 120-V power source, as shown in Figure P18.50. Find (a) the total power delivered to the three bulbs and (b) the potential difference across each. Assume the resistance of each bulb is constant (even though, in reality, the resistance increases markedly with current). Figure P18.50
Three 60.0-W, 120-V lightbulbs are connected across a 120-V power source, as shown in Figure P18.50. Find (a) the total power delivered to the three bulbs and (b) the potential difference across each. Assume the resistance of each bulb is constant (even though, in reality, the resistance increases markedly with current). Figure P18.50
A child’s electronic toy is supplied by three 1.58-V alkaline cells having internal resistances of 0.0200 in series with a 1.53-V carbon-zinc dry cell having a 0.100- internal resistance. The load resistance is 10.0 . (a) Draw a circuit diagram of the toy and its batteries, (b) What current flows? (c) How much power is supplied to the load? (d) What is the internal resistance of the dry cell if it goes bad, resulting in only 0.500 W being supplied to the load?
For the two resistors shown in Figure 17.12, rank the currents at points a through f from largest to smallest. (a) Ia = Ib Ie = If Ic = Id (b) Ia= Ib Ic = Id Ie = If (c) Ie = If Ic = Id Ia = Ib Figure 17.12 (Quick Quiz 17.8)
Consider the combination of resistors shown in Figure P18.8. (a) Find the equivalent resistance between point a and b. (b) If a voltage of 35.0 V is applied between points a and b, find the current in each resistor. Figure P18.8
When the switch is open in Figure 18.8, power Po is delivered to the resistor R1. When the switch is closed, which of the following is true about the power Pc delivered to R1? (Neglect the internal resistance of the battery.) (a) Pc Po (b) Pc = Po (c) Pc Po Figure 18.8 (Quick Quizzes 18.5 and 18.6)
Figure P18.19 shows a Wheatstone bridge, a circuit used to precisely measure an unknown resistance R by varying Rvar until the ammeter reads zero current and the bridge is said to be balanced. If the bridge is balanced with Rvar = 9.00 , find (a) the value of the unknown resistance Rand (b) the current in the 1.00 resistor. (Hint: With the bridge balanced, the wire through the ammeter can effectively be removed from the circuit, leaving two pairs of resistors in parallel.) Figure Pl8.19
For the circuit shown in Figure P28.55. the ideal voltmeter reads 6.00 V and the ideal ammeter reads 3.00-k. Find (a) the value of K, (b) the emf of the battery, and (c) the voltage across the 3.00-kft resistor.
Calculate the power delivered to each resistor in the circuit shown in Figure P21.43. Figure P21.43

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21.0 V, E2 15.0 V, and R = 17.0 .) In the figure below, find the following. (Let &1 E1 28.0 Ω 12.00 R (a) the current in each resistor A I2 = A I3 = A (b) the power delivered to each resistor P1 P2 = W P3 W