Question
Asked Nov 27, 2019
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21.3 gram of salt E(NO)3  are dissolved in 500 ml of solution.The concentration of (NO3-) is 0.6 mole/l.E has 14 neutrons.Which element is E?

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Expert Answer

Step 1

Given data:

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Mass of salt (E(No,),) = 21.3 g Volume of solution = 500 mL 0.5 L Concentration of NO; = 0.6 mol/L 0.6 M Number of neutrons present in E =14

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Step 2

The salt E(NO3)3 dissociates as follows.

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E(NO)E3NO

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Step 3

From the above equation, 1.0 M of E(NO3)3 gives 3.0 M of NO3-. Therefore, the concentration (molarity) of E(NO3)3 that gi...

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1M of E(NO,) 3 M of NO = 0.6 M of NO 0.2 M of E(NO;);

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