2-2).5%2T4 7CLeS)E2-z)E+A cell touer 1IS lecateclCenter af a smaltwn The cell tower has a radius a4mileS-ahouse islocatedl miles Nocth c the centexct the tawnandis tothe ast o the cell tauser.lf the houseliesmtrebaundax the celltouwer's Caeragous farCast the Cenler a tho ton, IS tachedseuules eastmiles Nof the

Question
Asked Sep 15, 2019
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Have you take in account the amount of space the tower takes up 

2-2)
.5%
2
T
4 7
CLeS)E2-z)E
+
A cell touer 1IS lecatecl
Center af a smaltwn The cell tower has a radius a4mileS
-ahouse islocatedl miles Nocth c the centexct the tawn
andis tothe ast o the cell tauser.lf the houselies
mtrebaundax the celltouwer's Caeragous far
Cast the Cenler a tho ton, IS tachedse
uules east
miles Nof the
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2-2) .5% 2 T 4 7 CLeS)E2-z)E + A cell touer 1IS lecatecl Center af a smaltwn The cell tower has a radius a4mileS -ahouse islocatedl miles Nocth c the centexct the tawn andis tothe ast o the cell tauser.lf the houselies mtrebaundax the celltouwer's Caeragous far Cast the Cenler a tho ton, IS tachedse uules east miles Nof the

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Expert Answer

Step 1

The cell tower is located 5 miles east and 10 miles north of the city’s center. Its coverage radius is 4 miles. The house is 7 miles north to the center and is on the east of the cell tower. Consider the diagram that depicts the situation.

н
5 miles east
4 miles
10-7-3
7 miles north
10 miles north
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н 5 miles east 4 miles 10-7-3 7 miles north 10 miles north

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Step 2

In diagram, a triangle is observed where x is the number of miles that represents the horizontal distance between the house H and the tower T and 10–7=3 is the number of miles that...

(x)'(3)(4)
abc2
x29 16
72.65
Thus, the number ofmiles, the house is away from the city's center in the east becomes
5 2.65 7.65
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(x)'(3)(4) abc2 x29 16 72.65 Thus, the number ofmiles, the house is away from the city's center in the east becomes 5 2.65 7.65

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