** 22. A box (mass 5.6 kg) sits 3 meters from the right-hand side of a 10-meter-long beam (mass 20 kg). The beam is supported on the left by a rope that is exactly 0.5 meters from the left end of the beam. On the right edge, Greg supports the beam on his head.
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- The Iron Cross When a gymnast weighing 750 N executes the iron cross as in Figure lN.91a, the primary muscles involved in supporting this position are the latissimus dorsi (lats") and the pectoralis major (pecs"). The rings exert an upward force on the aims and support the weight of the gymnast. The force exerted by the shoulder joint on the arm is labeled Fs, while the two muscles exert a total force Fw on the arm. Estimate the magnitude of the force Fw. Note that one ring supports half the weight of the gymnast, which is 375 N as indicated in Figure P8.91b. Assume that the force Fw acts at an angle of 45 below the horizontal at a distance of 4.0 cm from the shoulder joint In your estimate, take the distance from the shoulder joint to the hand to be L = 70 cm and ignore the weight of the arm.A crane of mass m1 = 3 000 kg supports a load of mass m2 = 10 000 kg as shown in Figure P10.36. The crane is pivoted with a frictionless pin at A and rests against a smooth support at B. Find the reaction forces at (a) point A and (b) point B. Figure P10.36A schoolyard teeter-totter with a totallength of 6.4 m and a mass of 41 kg is pivoted at its center. A 21-kgchild sits on one end of the teeter-totter. (a) Where should a parentpush vertically downward with a force of 210 N in order to hold theteeter-totter level? (b) Where should the parent push with a force of310 N? (c) How would your answers to parts (a) and (b) change if themass of the teeter-totter were doubled? Explain
- Three uniform spheres are fixed at the position shown. What are the magnitude and direction of the force and acceleration on an 0.0150 kg particle placed at P?(draw FBD)A block of mass M = 6.1 kg rests upon a beam of mass mb = 12.8 kg as shown. The beam has length L = 5.4 m, and the block is placed at a distance of d = 1.8 m from the left end of the beam. (a) Find the reading of scale A in N. (b) Find the reading of scale B in N.Two masses are attached to a uniform meter stick as shown in the figure below. The masses of m1 and m2 are as given and the meter stick weighs 150 g. A force F with unknown magnitude is applied on one end of the stick at an angle of 30° to balance the system. (a) What is the magnitude of F? (Ans: 6.21 N) (b) What are the reaction forces on the support? (Ans: Rx = 5.38 N; Ry = 5.80 N)
- The m = 420 gg mass in (Figure) is pushed across the 2.0-m-long cart by a 3.0 N force, starting at the left side. The coefficient of kinetic friction between the mass and the cart is 0.40. The cart's coefficient of rolling friction is 0.020. How far has the cart rolled when the mass falls off the right side? Express your answer with the appropriate units.A beam resting on two pivots has a length of L = 6.00 m and mass M = 88.0 kg. The pivot under the left end exerts a normal force n1 on the beam, and the second pivot placed a distance ℓ = 4.00 m from the left end exerts a normal force n2. A woman of mass m = 61.0 kg steps onto the left end of the beam and begins walking to the right as in the figure below. The goal is to find the woman's position when the beam begins to tip. Where is the woman when the normal force n1 is the greatest? X=0 c. (c) What is n1 when the beam is about to tip? 0 (d) Use the force equation of equilibrium to find the value of n2 when the beam is about to tip. (e) Using the result of part (c) and the torque equilibrium equation, with torques computed around the second pivot point, find the woman's position when the beam is about to tip (f) Check the answer to part (e) by computing torques around the first pivot point x =Consider the woman doing push-ups in the figure. She has a mass of 49.2 kg, and the distance from her feet to her center of mass is 0.96 m, while the distance from her feet to her hands is 1.75m. a. What force in newtons should the woman in the figure exert on the floor with each hand to do a push-up? Assume that she moves up at a constant speed. b. The triceps muscle at the back of her upper arm has an effective lever arm of 1.95 cm, and she exerts force on the floor at a horizontal distance of 15.5 cm from the elbow joint. Calculate the magnitude of the force in newtons for each triceps muscle. c. How much work in joules does she do if her center of mass rises 0.27 m? d. What is her useful power output, in watts, if she does 25 pushups in one minute? For the sake of simplicity, ignore any power used by her muscles lowering her body during each pushup.
- A beam of mass M and length L is hanging from a rope perpendicular to a wall. The rope is attached at a point that is 75% of the length of the beam. A second rope is attached to the end of the beam. On the second rope hangs a block with mass m. (a) Draw all forces acting on the beam in a free body diagram. (b) Write the equations necessary for equilibrium in terms of the forces for this situation. (c) Use the torque equation to solve for the tension.A beam resting on two pivots has a length of L = 6.00 m and mass M = 91.0 kg.The pivot under the left end exerts a normal force n1 on the beam, and the second pivot placed a distance ℓ = 4.00 m from the left end exerts a normal force n2. A woman of mass m = 62.0 kg steps onto the left end of the beam and begins walking to the right as in the figure below. The goal is to find the woman's position when the beam begins to tip. (b) Where is the woman when the normal force n1 is the greatest?x = m(c) What is n1 when the beam is about to tip? N(d) Use the force equation of equilibrium to find the value of n2 when the beam is about to tip. N(e) Using the result of part (c) and the torque equilibrium equation, with torques computed around the second pivot point, find the woman's position when the beam is about to tip.x = m(f) Check the answer to part (e) by computing torques around the first pivot point.x = mA beam resting on two pivots has a length of L = 6.00 m and mass M = 77.0 kg. The pivot under the left end exerts a normal force n1 on the beam, and the second pivot placed a distance ℓ = 4.00 m from the left end exerts a normal force n2. A woman of mass m = 61.5 kg steps onto the left end of the beam and begins walking to the right as in the figure below. The goal is to find the woman's position when the beam begins to tip. (b) Where is the woman when the normal force n1 is the greatest?x = (c) What is n1 when the beam is about to tip? (d) Use the force equation of equilibrium to find the value of n2 when the beam is about to tip. (e) Using the result of part (c) and the torque equilibrium equation, with torques computed around the second pivot point, find the woman's position when the beam is about to tip.x = (f) Check the answer to part (e) by computing torques around the first pivot point.x = (g)Except for possible slight differences due to rounding, is the answer the same for F…