25 m 25 m 18 m Il m Il m 48 m

Q: В m 3 m 4 m 4 m 4 m 4 m 3 m

A:

Q: 4 m 3 m 8 m 5 m

A: Surface area is the sum of areas of all faces.

Q: 14 m 12 m 17.5 m

A:

Q: 7. 8. 9 in. 5 m V146 m 7 in.

A:

Q: 1) 8.5 mi 5 mi 8.5 mi

A:

Q: 16 m 11 m 6.5m 7 m 6 m

A: To determine the surface area

Q: 40 ft 94 ft O 23 О 25 41 О 65

A:

Q: 41 m 14 m 13 m 17 m Area m?

A:

Q: 50 ft 60 ft 35 ft Find h. O 35.60 O 35.00 O 35.71 61.03

A: From the Pythogoras Theorem

Q: hey take 6 ind m. 3.875 m. 3.

A: Given: Individual meter stick measurements of six students. To find: Length of the hall way

Q: 8. mHJ 29 53 96 E

A:

Q: 70.7 m 100 m 42 45 48 52

A:

Q: 10* 10 + c

A:

Q: 13 m 5 m 12 m 28 cm 35 сm

A: Area of triangle = 12×b×h Where b is base and h is height of triangle. Area of rectangle = l×b Where…

Q: 36.4 28 E 49 –

A:

Q: 12 m 6 m 8 m 10 m

A:

Q: 309,63 m 325 m 276,13 m | 149,23 m 91,13 m| |115,73 m 57,63m 74,24 m 124,90 m

A: Solution: The division table is ÷ 57.63 74.24 91.13 115.73 124.90 149.23 276.13 309.63 325…

Q: 7 m 8 m 7 m 14 m 7 m 7 m

A: The figure is a rectangular prism.

Q: 1. 6 m 107 38 15 in 2.

A: Given: 1) 2)

Q: 9 m 7 m 5 m 3.6 m 10 m

A: Volume is produced area of base and hight

Q: 6. 25 m 36 m 17.9 m. 21 m 14 m

A: Area of prism is given by, Area of base × height of prism

Q: apezoi (А) 16 сm в) 15 сm 12 сm 10 сm

A: We will find the 4th side.

Q: 20° 30 m О 10.91 m О 11.55 m О 28.19 m 82.42 m

A: the given figure is: we have to find the value of x.

Q: 15 сm 28 сm 25.7 ст 20 ст 37 сm

A:

Q: (34)(35) = O 620 O 99 O 39 320

A: we have to solve the following

Q: 2 m 2 m 2 m 3 m 3 m 6 m

A: calculate area separately

Q: 15 m 1.7 m 25.5 cu m 80 cu m 43.4 cu m 136.1 cu m

A:

Q: (3.54m)_ (60.5m)(17m)(28.8m) (10.5 m)x(28.75 m) + 3020m 29.7m

A:

Q: 5 m !5 m 8 m 12 m

A: Given

Q: 12. 13. 14. 15 in 18 in 5 ft 97° 20 in 5 ft 102 AM 4/13/2021

A:

Q: 35 m 38 m 32.7 m 13 m 35 m 17.6 mm 7. 8. 10 yd 19 yd 7.8 yd 19 yd 10 yd 44 in J.

A: We can find the area for the questions as below.

Q: 10 78 E. 78 12

A:

Q: 36 15 m O 8.81 ft O 18.54 ft O 20.65 ft O 25.52 ft

A:

Q: 8 m. 5 m. 6 m

A: The area of the shaded part in the given figure can be obtained by subtracting the area of the…

Q: 20 18 M 12 117 78 130

A:

Q: 18. 200 m 120 m 40 m 60 m

A: As it is mentioned to find the area of 18th question, we will solve it.

Q: 22° 85 ft O 25.13 ft O 31.84 ft 34.34 ft O 78.81 ft

A:

Q: 7.8 km E 16 km - SA=

A:

Q: 34. 10 m 16.5 m 8 m 5 m

A:

Q: 4. 5, 8. 3. 6. 55* 7 m/1 = m25 = 2.

A: Given that: A rhombus with one angle 55°.

Q: 2) 28 m 17 m B 15 m C

A: Solving the area of the given triangle.

Q: 19) 20) 5,1 mi 8.4 yd 3.6 yd 4.4 yd 5.1 mi 42 yd 5.1 mi

A:

Q: 68 m<1= 61 m<2= m<3= 13 = 17 m22 = m23 = 2.

A: “Since you have asked multiple question, we will solve the first question for you. If youwant any…

Q: 24 m 35 m 40.4 m

A:

Q: 7. 2 ft 40- 40 2 ft 9. 10. 2 ft 6 ft 60 40 11. 12. 6 ft 15 m 60 20

A: Explanation of the solution is given below....

Q: 6 m 7 m 5 m

A:

Q: 30 ft Wall 32 1) 15.9 ft 2) 18.7 ft 3) 25.4 ft 4) 56.6 ft

A:

Q: 11 m 12 m 15 m 13 m 25 m A = m2

A: First we divide the figure into three parts two triangles and one rectangular. Then we find the…

Q: 3.5 m 4 m 4 m 4 m 5 m O 76 square meters O 54 square meters O 74 square meters O 60 square meters

A: Calculate the area of triangles and rectangle and add them to get the total area.