Question
Asked Oct 7, 2019
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Use implicit differentiation to find an equation of the tangent line to the curve at the given point. 

 

The equation is provided as the attached image. 

28. 22a4y2 = 12, (2, 1) (ellipse)
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28. 22a4y2 = 12, (2, 1) (ellipse)

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Expert Answer

Step 1

Given equation of curve is

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+2xy 4

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Step 2

We differentiate both sides of equation with respect to x

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x2 2xy 12 dy 2x 2x +y8y dx dy dx dy (2x + 2y) dx (2x+8y) 2х + 2y dy 2x+8y dx dy x y x + 4y dx

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Step 3

Slope of tangent to curve f(x,y)=0 at point ...

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dy т %3 2+1 1 2+4(1) 2 |

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Tagged in

Math

Calculus

Derivative