2NaHCO3(s)--> Na2CO3(s)+CO2(g) +H2O(l)When 30.0 g NaHCO3 decomposes, the change in energy is-23.1 kJ. Use this information and the additional information provided to calculate the ΔH°f of NaHCO3. SubstanceΔH°f (kJ/mol)H2O(l)–286CO2(g)–394Na2CO3(s)–1131ΔH°f of NaHCO3  ___kJ/mol   ?

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Asked Nov 22, 2019
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2NaHCO3(s)--> Na2CO3(s)+CO2(g) +H2O(l)

When 30.0 g NaHCO3 decomposes, the change in energy is-23.1 kJ. Use this information and the additional information provided to calculate the Δf of NaHCO3.
 

Substance Δf (kJ/mol)
H2O(l) –286
CO2(g) –394
Na2CO3(s) –1131


Δf of NaHCO3  ___kJ/mol   ?

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Expert Answer

Step 1

Given:

2NaHCO3(s)--> Na2CO3(s)+CO2(g) +H2O(l)

Step 2

Calculation for moles of NaHCO3:

mass
number of moles
molar mass
30 g
number of moles
84.007 g/mol
number of moles = 0.357 mol
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mass number of moles molar mass 30 g number of moles 84.007 g/mol number of moles = 0.357 mol

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Step 3

Calculation for Enthal...

ДНҒО
23.1 KJ
ДНҒО
0.357 mol
AHF° = -64.70 KJ/mol
For 2 moles of NaHCO3 (AHf°) = 2 x 64.70 =-129.4 KJ/mol
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ДНҒО 23.1 KJ ДНҒО 0.357 mol AHF° = -64.70 KJ/mol For 2 moles of NaHCO3 (AHf°) = 2 x 64.70 =-129.4 KJ/mol

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