2s +3 F (s) = s(s2 – 2s + 5)

Q: f (x, y) = 3x²: f (x, y) = x² + 3y²: f (x, y) = y – 2x?: f (x, y) = 5x² – 5y²:

A: The function f(x,y)=3x2  Level curves are made by fixing values of fx,y=k.…

Q: . Эn Эт (п + т-4лп-т%3D1) . Эп Эт (п + т %3D 4лп-т 3D2) . Vn Vm 3p (p= (m + n)/2)

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Q: 2s a) F(s) s2 – 2° s + 3 b) F(s) = s2 + 2s + 4

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Q: (a) Y(s)-e-5s (85-3) s²+6s+12

A: We are authorized to answer one question at a time, since you have not mentioned which question you…

Q: v² =v² +2a(s-s) i. j. K = = kx² 2 k. T = 27 е g ,a = ,X = ,g =

A: This question can be solved using the concept of explicit function.

Q: f(t) = te3t cosh 4t s²-6s+7 s2-6s-7 А. (s2-6s+25)2 С. C. (s2-6s-25)2 s2-6s+25 В. (s2-6s-7)2 s2…

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Q: 1 F(s) F(s) s2-6s+34 s2 +4s+4 s2-4s+53 s2-6s+9 This option This option

A: Laplace transform

Q: 2s +10s F(s)=D (s²–2s +5)(s+1)

A: As per our guidelines we are supposed to answer only 1st one. Please repost 2nd question. Thank you…

Q: Determine L-1{F(s)} 2s+1 sF(s) + 3F(s) s2+2s+1

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Q: n: y" – 9y = 0; e3x; e-3x

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Q: f(s) -3s² – 5 %D S f(s) -2 -1

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Q: 2s – 3 - 1. F (s) (s – 2)²(s + 5) 2s 2. G(s) = s2 + 8s + 25

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Q: Sį : -8(y – 2) = (x – 1)² S2 : y + z = 2 S3 : x = 0 S4 : y = 0 S3 : z = 0 %3D

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Q: 3s - 2s - (s-3)(s² +1) %3D (1 + ;s)(E = $) = (s)d

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Q: 8s – 3 F(s) s2 – 36

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Q: L[(t + 1)2e] = ? %3D s2-1 s2 +1 (s-1)2 (s – 1)2 -

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Q: 2s (s² + 1)² 3) Find L¹ 40 by using the convolution theorem.

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Q: (d) F(s) = - 1- e-s s2 +s - 2 (е) F(s) - s3 – 3s + 2

A: (-2 δ(t) + δ'(t) + δ''(t))/(s^3 - 3 s + 2) = (-2 δ(t))/(s^3 - 3 s + 2) + (δ'(t))/(s^3 - 3 s + 2) +…

Q: X(s)=(s^2+6s+7)/(s^2+3s+2) and Re{s}>-1 what is x(t)?

A: We are given : X(s)=s2+6s+7s2+3s+2 ⇒X(s)=s2+3s+2+3s+5s2+3s+2 ⇒X(s)=1+3s+5s2+3s+2 ---(1) Now,…

Q: determine L−1[F].

A: Given that, Taking inverse Laplace transform from both sides, By using L-1{aF(s)] = aL-1{F(s)}; a…

Q: s2 + 11s + 20 1-J = (1)h (q) (s² + 4s + 8)(s + 1)² J* %3D

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Q: 3 x = y + z- w = 2 -x + 2y - z - w = -1 2x - y - z+ w = 4 x + 3y - 2z - 3w = 6

A: 3

Q: 5r+1 (d) 16 - 2>0 (e) 2 4

A: Solution set of inequality are following

Q: L(cosh 4t) = %3D .a s²-16 .b O s2 – 8 .cO s²+16 S

A: option :- a

Q: 교고 + z-2 I+ -2, b) f(x) = I+2 -3, I = -2;

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Q: 2Fs1 ² f (x, y) dx² proof. (H-w-) 2 ./ = P√= f (gy) - P²Fs (Psy) ар(х,у) 0 as x If f (x,y) → 2

A: Introduction: A Fourier transform (FT) is a mathematical transformation that decomposes capabilities…

Q: 1) e - 3 s2 -7 2) -la 2 (s – 3)5 7s 3) C-1 s2+4

A: As per our company guidelines we are supposed to answer only first 3 sub-parts. Kindly repost other…

Q: у" +2y' + у %3 6 (t - 1) + e2t у (0) %3 0, у' (0) —0

A: The general form of a second-order nonhomogenous linear differential equation is given by…

Q: a) z=-x² + y² c) z² = x² + 2y² e) x² + y²-z² = 1 b) z=-x²-2y² d) -x² - y² + z² = 1

A: match the following quadratic surfaces with the following equations (a) z=-x2+y2

Q: f(s) = s² +5 2 3s³+2s²+5s find f(t)

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Q: 3. F(s) 2(s – 1)e-25 s²+2s-2 2e-2s 4. F(s) s2–4

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Q: y fa(4y) -1.0 -2 1/8 -0.5 -1 1/4 1/2 1/8 0.5 1 1.0 2 Find the E (X), E(Y), V (X), and V (Y). 2.

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Q: z = 2 24 z=Vx² + y² 2 FIGURE 9

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Q: s³ - 7s² +14s -9 23) F(s): = (s) (s-1)°(s – 2)' Ans. f(t) = te' -0.51'e %3D

A: Solution is given below:

Q: f(t) = te3t cosh 4t s2-6s-7 А. (s2-6s+25)2 s2-6s+7 С. (s2-6s-25)2 s2-6s+25 3. (s2-6s-7)2 s2-6s-25 D.…

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Q: Y"'-y"+y'-y=xe^x-xe^-x+7 by using  Variation of parameters  methode

A: first, we will find the values of y1 and y2 by equating the equation equal to 0 we get…

Q: 3s (s-2)2 3e2 (1 – 21) 3e-21 (1 + 2t) In (출) 3te-21 3e2" (1 + 2t) 3t e2 6te2

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Q: s(x)= 2x2 t(x)= 3X (S x t)(X)= (S+t)(X)=  (S-t)(-2)=

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Q: 3s 4) F (s) s2+2s-8 10-4s 5) F (s) (s-2)2 s+12 6) F (s) s2+4s ||

A: Inverse Laplace transform 1/(s-a) = e^(at)  Inverse Laplace transform 1/(s-a)^2 =t e^(at)

Q: 2. Зу"-14y-5y-0 ans: y=cje" x+ (-1/3)x

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Q: 2X + y - x - 2y + 2z = -11 3x - y + z = (x, y, z) =

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Q: Using convolution theorem, find 1 L-1 s4(s² + 16)

A: Given L-11s4(s2+16) Let F(s)=1s4 and G(s)=1s2+16

Q: fo 뉴- 토욜 하블 4+0 X = 2 (-1,4] find MLE (0) GE | + 旦22 0 + ㅈㅈ =-2 7= 1 1

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Q: (ii) y" – 4y' + 4y = e3", y(0) = 0, y'(0) = 0. %3D

A: We have to find general solution of the given initial value problem.

Q: 2s – 3 F(s) s2 + 2s + 10

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Q: 3s F(s) = s2 – s – 6 s - 6

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Q: + Vs + es +- ds n = 3 From left endpoint s² + 1

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Q: (D² – 4)y = 2 – 8x; when x = 0, y = 0, y' = 5. %3D ANS. y = e2x – e-2* + 2x – }.

A: We have to find solution of given differential equation.

Q: 2s2 + s+3 F(s) = %3D (s- 1) (s+ 2)2

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Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.