[(2x -1)3– x )dx = + 8. 0 3.

Q: d (e) -[3r + 2n*) = 15x* + 873 %3D dx

A:

Q: S. 2 dx x(3(\nx)*+121nx-15)2

A: Solution:-

Q: -2 (x – 1)(7x + 7) dx = 2.

A:

Q: 10a3 5.) dx 1 – x8 -

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Q: (-1)^ dx n= (2n+1)!

A:

Q: dx -3 x(x+1)

A: We know, ∫dxx-a=ln(x-a)

Q: dx 4. S; x2Vx2-1

A: Given: I=∫dxx2x2-1   ...1 As we know that; The trigonometric identities; 1). sec2x=tan2x+1 2).…

Q: (メ+4) dx x2 + 2x+5

A: Integration is summation of discrete data. The integral is calculated for the functions to find…

Q: L dx x-1 -1 -x²+1

A:

Q: 30. G(x) %3D х3 -5e2х

A: Given  G(x)=x3-5e2x Now we have to find the difference of G(x) as shown below

Q: 2 X 1 dx -2 4

A: Let's see a formula of integration. ∫a2-x2 dx = x2a2-x2 + a22sin-1xa + C We use this formula to…

Q: S 23x* + 5 +* x2-16 dx X-4

A: We will use simple Integration rules to solve this question.

Q: +). L x-1 dx -1x2+1

A:

Q: 2.x dx x² + 2x + 5

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Q: d.) s 2x+3 x243x-1 dx

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Q: e4z+1 dx e2r – 1 17.

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Q: S (3K +8e -x) dx

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Q: 4 + x² dx 2

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Q: 1 b. 4*(x³)dx -1

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Q: -5x +3x – 28 dx (x – 1)(x² + 9)

A:

Q: evaluate the integral.

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Q: 1 dx = 20+8x-x2

A:

Q: Find the following indefinite integrals:

A: Now,

Q: - 30 + 8x² | + 8a° dx =

A:

Q: 1 dx -x2-4х+ 12 X.

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Q: -8x2 + 16x + 8 dx (x – 1)2(x² + 1)

A:

Q: 2x-1 ate dx by using substitution m

A:

Q: e2a+1 dx 3. .

A: the given integral is: ∫e2x+1dx we have to evaluate the given integral.

Q: √(x + 3) dx √16-x²

A: Solution

Q: x*dx 3. S x2-1

A: use a partial fraction to solve the integral.

Q: 7x dx 19. (1 – x²)3

A:

Q: dx 1) S- x2-2x+1

A: As per the guidelines we can only solve one question post other question seperately. Formula used  ∫…

Q: ii) ∫7x-25/(x-3)(x-4) dx

A: Given,          ∫7x-25x-3x-4dx

Q: Compute dx. x2 + 4x + 8

A: Our Aim is to compute the integral given below:-∫02 xx2+4x+8dx -(i)

Q: a) Evaluate -5 S₁v 1 √√4 − (x − 3)² dx -

A:

Q: x² dx -1 (2x²+2x+1)² sº₁

A: We have to evaluate the integral. ∫dxa2+x2=1atan-1(xa)+c

Q: 2x?+9х-1 1. S x(x2-1) dx

A:

Q: Vx - 2 dx 5 x + 1)

A:

Q: x² dx. Evaluate: /2x3 -1 -1

A: We have to evaluate the integral

Q: X dx 2-1

A:

Q: -9 (x-1) 8. √x dx

A:

Q: dx Evaluate -1 x2 - 0 -2

A: The integration formula is ∫xndx=xn+1n+1+C.

Q: 10 dx. (-1)(x²+9)

A: We have to find integral.

Q: 2tan-1(x) dx = - In2 2 (b)- In4 (0) + In2 (d); - mn

A: Given:- I=∫012tan-1(x)dx

Q: dx 13. / 2√²²2-1 x > 1

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Q: iv) L,x²e=* dx -2 -3x dx 1

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Q: x3-1 dx J2+2x+5

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Q: -2 х 6. dx 1-x

A: Topic = Integration use ∫1xdx=lnx+Clnx⇒x is NOT defined for negative values of the independent…

Q: x2 – 25 dx 7) S-

A: