3 -6 -6 3 -6 and v = 1 Verify that 9 is an eigenvalue of A and v is an eigenvector. Then orthogonally diagonalize A. Let A = -6 -6 The number 9 is an eigenvalue of A with eigenvector (Type an exact answer, using radicals as needed.) The vector v = 1 is an eigenvector of A with eigenvalue - 9 . (Type an exact answer, using radicals as needed.) Orthogonally diagonalize the matrix, giving an orthogonal matrix P and a diagonal matrix D. Enter the matrices P and D below. (Use a comma to separate matrices as needed. Type exact answers, using radicals as needed. Do not label the matrices.) 6.
3 -6 -6 3 -6 and v = 1 Verify that 9 is an eigenvalue of A and v is an eigenvector. Then orthogonally diagonalize A. Let A = -6 -6 The number 9 is an eigenvalue of A with eigenvector (Type an exact answer, using radicals as needed.) The vector v = 1 is an eigenvector of A with eigenvalue - 9 . (Type an exact answer, using radicals as needed.) Orthogonally diagonalize the matrix, giving an orthogonal matrix P and a diagonal matrix D. Enter the matrices P and D below. (Use a comma to separate matrices as needed. Type exact answers, using radicals as needed. Do not label the matrices.) 6.
Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter7: Eigenvalues And Eigenvectors
Section7.2: Diagonalization
Problem 32E
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