Question
Asked Dec 16, 2019
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The first question is the one I need answered. 

3.
6.
2.
5.
4.
2.
1.
40°H°0
3.
6.
3.
2.
1.
CAH100
1.
6.
For each NMR spectrum, draw the structure of the following compounds. Molecular formulas are given.
Practice NMR Problems
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3. 6. 2. 5. 4. 2. 1. 40°H°0 3. 6. 3. 2. 1. CAH100 1. 6. For each NMR spectrum, draw the structure of the following compounds. Molecular formulas are given. Practice NMR Problems

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Expert Answer

Step 1

In H-NMR, the intensity of the peak indicated the number of same types of Hydrogen atoms.

Also, splitting of a peak in H-NMR occurs due to presence of adjacent hydrogen atoms. The splitting of a proton gives (n+1) peaks, where n is the number of adjacent hydrogen atoms.

Step 2

From H-NMR spectrum, we can observe the following:

  • A singlet (1 peak) for 1 H at 4.2 which indicates the presence of -OH group. The hydrogen is marked as ‘a’ in the figure.
  • A doublet (1+1) for 2 H at around 3.7 indicates the presence of hydrogen (marked as ‘b’ in the figure) that are adjacent to a -CH- group. And this doublet is formed at higher chemical shift value due to the pr...
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6H CAH100 ҫн, гн --сн-о-н 1H 1н Н—С—СН-0-н CH,

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