3. Consider the following enzyme-catalyzed reaction of urea Urea + Urease (Urea. Urease)-> 2 NH, + CO2-urease ES The rate of reaction is given below as a function of the urea (substrate S) concentration Curea, kmol/m .30 0.65 0.25 0.17 0.061 0.0008 urea kmol/m-s 12.60 5.50 3.09 2.05 0.293 0,0035 a. Using Excel, determine the Michaelis-Menten rate equation parameters ra (also called V and K. by using the Lineweaver-Burke, Eadie-Hofstee and Hanes-Woolf equations (three separate plots). Show the model-predicted fit and clearly identify the three sets of rate equation parameters along with the regression statistics b. Using the above three sets of rate equation parameters, generate predicted values for ) vs Cs from Cs-0 to Cs-1.40 using a spacing of ACs-0.02. Compare the -S Cs data (solid points) with the predicted values using the rate equations parameters identified in step 2. (Lineweaver-Burke - solid line; Eadie-Hofstee-dashed line, and Hanes-Woolf- dotted line). Make sure to include a plot legend. e. Comment on the fit of the M-M curves from the estimates of kinetic parameters made in Part (a). Which approach was the best fit for the data? Explain why by looking up the three linear forms from an existing literature source and commenting on their statistical 'bias

Q3. Péclet number – We've seen the Péclet number Pé = vl as a useful metric to D determine if stirring (Pé > 1) is more efficient than diffusion (Pé < 1) for mixing solutions. "Stirring" here can designate any process which applies a force on the molecules, resulting in a velocity v. a) Show that the Péclet number, like the Reynolds number, is unitless. Let's think about why scale (f) matters for mixing. 1-DNA, a DNA polymer containing 48,502 base pairs, has a diffusion coefficient of D = field of 1 V/m, we can expect 1-DNA to reach a terminal velocity of 30 nm/s. 6.4 x 10-13m²s=1. Under an electric

More Gr 1.0mm 1- A bioreactor is a vessal in which biological Conversion. is carried out involving enzymes, microorganisms, and/or animal and plant Cells. In the anaerobic fermentation of grain, the yeast Saccharomy Ces Cerevisiae digests. glucose (C6H12 06) from plants to form the products. ethanol (Cz Hs oH) and profenoic acid (C₂ H₂ Co₂ H) by the following reactions = - Reaction / C6H₁2O6 2 C₂ H₂H + 2 Co₂ 12 Reaction 2: C6H12O62 C ₂ H 3 Co₂ H + 2 H ₂0 In a batch process, of a tank is charged with nooo kg 12% solution of glucose in water. After fermentation, 120 kg of. Co₂ are produced and go.kg of unreacted glucose remains in the broth, what are the weight (mass) Percents of ethanol and Pro Penoic acid in the broth at the end of the fermentation process ? Assume that none of the glucose is assimilated into the bacteria.

Problem 2: Liquid-liquid extraction A liquid feed stream of 1500 kg/h consisting of 35 wt. % acetonitrile (1) and 65% water (2) is to be extracted using isobutyl methyl ketone (3) as the solvent. If the flow rate of the solvent is 500 kg/h, determine the flow rates and compositions of the exit streams using the phase diagram (mass fractions) below. The overall process takes place at a constant temperature of 303 K. Acetonitrile OA 1 Extract Phase 0.2 0.8 0.4 0.6 F 0.6 E 0.4 F M 0.8 0.2 Raffinate Phase Isobutyl 1 methyl ketone 0.2 0.4 0.6 0.8 1° Water Settler,

3. Carbon tetrachloride (CC14) can be produced using the following reaction. If 34.535 grams of chlorine (Cl2) produced 28.550 g of CC14, what is the percent yield of this reaction? C(s) + 2 Cl2(g) CCI4(1)

Macmillan Learning One way to synthesize ethylamine (CH₂CH₂NH₂) is from the reaction of ammonia (NH3) with chloroethane (CH₂CH₂CI). (1) NH3 + CH₂CH₂Cl → CH₂CH₂NH₂ + HCl One problem with this synthesis route is that the reaction is not very selective, and ammonia may react with two chloroethane molecules to form diethylamine ((CH₂CH₂)₂NH). (2) NH3 + 2 CH₂CH₂Cl (CH₂CH₂)₂NH + 2HCl A mixture of x₁ = 0.465 mol NH3/mol, x2 = 0.465 mol CH₂ CH₂Cl/mol, and the remainder inerts is fed into a reactor. Within the reactor, the fractional conversion of CH3 CH₂Cl is 0.750 and the fractional yield of CH₂ CH₂NH₂ is 0.410. [Fractional yield is the (moles of desired product formed)/(moles of product possible for complete conversion of the feed to the desired product).] Assume a 100 mol basis for the feed stream, and calculate the number of moles of each component entering the reactor and leaving in the product stream. Here is the process flow diagram for reference. 100 mol mol NH3 /mol X₁ x₂ mol…

Hypochlorous acid (HOCI) is a weak acid that dissociates into hypochlorite (OC1-). HOCI is the active form of chlorine in water and thus is important for disinfection. In designing a disinfection process, it is important to know that HOCI is 80-120 times more effective as a disinfectant than OCI-. a) Write a mass balance equation for CTOT,OCI.

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Label the acid, base, conjugate acid and conjugate base in the following reactions: a.) NH3 (aq) + H2O (l) ⇌ NH3+ (aq) + OH– (aq)   b.) H2S (g) + HF (aq) ⇌ F– (g) + H3S+ (g)   c.) HCl (g) + CH3OH (g) ⇌ CH3OH2+ (g) + Cl– (g)

Hydrodealkylation is a process in which side chain alkyl groups (like methyl) are removed from aromatics by reaction with hydrogen. The following reactions take place in the reactor: C6H₂CH3 + H₂C6H6 + CH4 C6H4(CH3)2 + H2CH₂CH3 + CH4 E3 C6H₂(CH3)3 + H₂C6H4(CH3)2 + CH4 In addition, an unwanted side reaction occurs, in which benzene dimerizes to form diphenyl [C6H5C6H5] E4 2 C6H6 C6H5C6H5 + H₂ A process stream containing 5 mol% benzene [CH], 20 mol% toluene [C6H5CH3], 35 mol% xylene [C6H4 (CH3)2], and 40 mol% pseudocumene [C6H3 (CH3)3] is fed to a hydrodealkylation plant. This process stream is mixed with hydrogen gas in 5:1 gas-aromatics ratio before being fed to the reactor. A condenser separates hydrogen and methane from the other reactor products (lumped as aromatics). Feed ?B ?T ? X ?? ?P Reactor Hydrogen Gas ? H₂ Light Gases ? H₂ ?M Condenser Aromatics ?B ~~~.. BTXPD ?T ?X ?P ?D 1 b. For a basis of 100 moles of Aromatics, the component balance for toluene can be written: 12.3 = ?…