3. The first-order reaction, SO2C12 → SO2 + Cl2, has a rate constant equal to 2.20 × 10-$ s at 593 K. What percentage of the initial amount of SO,Cl2 will remain after 2.25 hours?

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Q: The first-order reaction, SO2C12 –→ SO2 + Cl2, has a rate constant equal to 2.20 x 10s will remain…

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Q: -1 The first-order reaction, SO2C12 → SO2 + Cl2, has a rate constant equal to 2.20 x 10 s at 593 K.…

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Q: The first-order reaction, SO2Cl2 → SO2 + Cl2, has a rate constant equal to 2.20 × 10-5 s-1 at 593 K.…

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Q: The first-order reaction, SO2C12 - SO2 + Cl2, has a rate constant equal to 2.20 × 10-5 s-1 at 593 K.…

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