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3.1.11Question HelpFind the slope of the function's graph at the given point. Then find an equation for the line tangent to the graph there.f(x)= x2+3, (2,7)What is the slope of the function's graph at the given point?m(Simplify your answer.)Enter your answer in the answer box and then click Check Answer1partremainingClear AllCheck Answer

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3.1.11
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Find the slope of the function's graph at the given point. Then find an equation for the line tangent to the graph there.
f(x)= x2+3, (2,7)
What is the slope of the function's graph at the given point?
m
(Simplify your answer.)
Enter your answer in the answer box and then click Check Answer
1
part
remaining
Clear All
Check Answer
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3.1.11 Question Help Find the slope of the function's graph at the given point. Then find an equation for the line tangent to the graph there. f(x)= x2+3, (2,7) What is the slope of the function's graph at the given point? m (Simplify your answer.) Enter your answer in the answer box and then click Check Answer 1 part remaining Clear All Check Answer

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Step 1

Consider the given function and given points.

f(x) x +3,
P(2,7)
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f(x) x +3, P(2,7)

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Step 2

On differentiating with respect to x,

f(x)2x+0
f'(x) 2x
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f(x)2x+0 f'(x) 2x

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Step 3

So, the slope of the function...

та —Г(2)-2x2
(2,7) = 4
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та —Г(2)-2x2 (2,7) = 4

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Calculus

Derivative

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