3.39 The diagram shows a conical section fabricated from pure aluminum. It is of circular cross section having diameter D = ax2, where a = 0.5 m². The small end is located at x₁ = 25 mm and the large end at x₂ = 125 mm. The end temperatures are T₁ = 600 K and T₂ = 400 K, while the lateral surface is well insulated. +1.x₂ ·X₂² (a) Derive an expression for the temperature distribution T(x) in symbolic form, assuming one-dimensional conditions. Sketch the temperature distribution. (b) Calculate the heat rate q.. 3. 3.-

Elements Of Electromagnetics
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3.39 The diagram shows a conical section fabricated
from pure aluminum. It is of circular cross section
having diameter D = ax2, where a = 0.5 m². The
small end is located at x₁ = 25 mm and the large end
at x₂ = 125 mm. The end temperatures are T₁ =
600 K and T₂ = 400 K, while the lateral surface is
well insulated.
+1.x₂
·X₂²
(a) Derive an expression for the temperature distribution
T(x) in symbolic form, assuming one-dimensional
conditions. Sketch the temperature distribution.
(b) Calculate the heat rate q..
3.4
3.4
Transcribed Image Text:3.39 The diagram shows a conical section fabricated from pure aluminum. It is of circular cross section having diameter D = ax2, where a = 0.5 m². The small end is located at x₁ = 25 mm and the large end at x₂ = 125 mm. The end temperatures are T₁ = 600 K and T₂ = 400 K, while the lateral surface is well insulated. +1.x₂ ·X₂² (a) Derive an expression for the temperature distribution T(x) in symbolic form, assuming one-dimensional conditions. Sketch the temperature distribution. (b) Calculate the heat rate q.. 3.4 3.4
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