3.55 The concrete pier is subjected to soil pressure that causes the line loads shown. Determine the resultant of the loading and find the y-coordinate of the point where the resultant crosses the y-axis. 6 MN/m 4 MN/m 4 m 8 MN/m Figure P3.55
Q: Consider a 125-mm-long segment of a simply supported beam. The internal bending moments on the left…
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Q: Consider a 130-mm-long segment of a simply supported beam. The internal bending moments on the left…
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Q: onsider a 140-mm-long segment of a simply supported beam. The internal bending moments on the left…
A: Given data: ∆x=140 mmM1=55 kNM2=58 kN
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A: As per guidelines we need to answer only first question. Shear stress=0.2kg/m2 =9.81*0.2 N/m2
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A: Taking Moment at E point ∑ME=0VA×11+1.4×4×1+42=4.2+3.2×112×114+5.2cos35×2 11VA+16.8=111.925+8.52…
Q: Consider a 140-mm-long segment of a simply supported beam. The internal bending moments on the left…
A: Given , The value of long segment of a simply supported beam is 140 mm . The bending moments on the…
Q: Q.2 The resultant of the force system shown in Figure (2) is a vertical force of 1250N. Determine…
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Q: Q.2 The resultant of the force system shown in Figure (2) is a vertical force of 1250N. Determine…
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Q: Figure 1: The vertical force at A is: A) 21.58 N B) 67.42 N C) 78.14 N (D) 192.19 N B 0.75 m 55⁰ A…
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Q: Consider the beam shown in (Figure 1). Suppose that wi = 600 N/m, w2 = 300 N/m. Follow the sign…
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Q: Consider a 130-mm-long segment of a simply supported beam. The internal bending moments on the left…
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Q: Consider a 155-mm-long segment of a simply supported beam. The internal bending moments on the left…
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Q: Consider a 155-mm-long segment of a simply supported beam. The internal bending moments on the left…
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Q: Q1: Determine the magnitude and direction of the resultant forces in figure below? Fq= 500 N F,- 600…
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Q: 80 mm Problem 2 For the shown beam, calculate the shear stress a) at point a b) at point b 160 mm…
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Q: 3.55 The concrete pier is subjected to soil pressure that causes the line loads shown. Determine the…
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Q: 4. Block B weighs 200N and block C weighs 100N. See Figure4. Determine the weight of block D and the…
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A: The given data is: Width of plain concrete slab (bc) = 6 m Thickness of plain concrete slab (hc) = 4…
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Q: 150 MM Q1/ 30 MM 60 мм IF : N.A I= 27 * 10° mm 120 MM V= 19.5 KN Determine the maximum and minimum…
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Q: Q1.2:Resolve the horizontal 600-1b force in Figure into components acting along the u and axes and…
A: Given: Horizontal force=600 lb Using sine law: Fusin 120°=600sin 30°Fu=1039lb
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A: Given:-A1=A2=900 mm2E1=E2=100GPah=1200 mmθ=60 degreeα1=α2=12*10-6/oC△T=35oCTo find:-Displacement at…
Q: Determine the support reaction at D using Conjugate Beam Method. Indicate the negative sign if the…
A: Solution: Given Data; E=200 GPaI=300×106 mm4
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Q: 2. A beam with an overhang is subjected to a combined loading, as shown in Figure 4. Determine the…
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Q: QUESTION 3: A block with mass m= (24+12)kg is pulled by a horizontal force P applied at point B in…
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Q: PROBLEM 2: The 200 kN block shown has impending motion up the plane caused by the horizontal force…
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Q: P=2,900 kN (parabolic) P=1,100 kN 0.05 0.45 m. 0.30 0.15 0.45 m. A' 0.075 EO E 0.45 m. 6.0 m. 6.0 m.…
A: Given force in Parabolic tendon, P=2900KN force in Linear tendon, P=1100KN,…
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Q: A horizontal bar of negligible mass is hinged at A and assumed to be rigid. It is supported by an…
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Q: 24 kN P. 5.78 The beam AB supports two concentrated loads and rests on soil that exerts a linearly…
A: Centroid of the two downward force vectors FTOT = 24+30 kN→XTOT = 0.624 + 1.53054 = 1.1 m
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Q: Consider a 200-mm-long segment of a simply supported beam. The internal bending moments on the left…
A: Given, B.Mat left =MA=70 kN-mB.Mat right =MB=74 kN-mb1=155 mmb2=30 mmb3=245 mmd1=65 mmd2=200 mmd3=65…
Q: Consider the beam shown in (Figure 1). Suppose that wi = 600 N/m, wz = 300 N/m. Follow the sign…
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Q: Refer to the figure shown. Draw shear and moment diagram and determine: 180 N 6 m 1 m Vertical…
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Q: 1 30mm 2 30mm 3 30mm 4 300mm -300mm F100mm- 100mm - -200mm- -200mm- 400mm 5 50mm a) Draw the shear…
A: A1 = 30×200+200+50 = 13500 mm2 & Y1 = - 302 = -15 mmA2 = 30×100+100+50 = 7500 mm2 & Y2 = -…
Q: A 300 mm diameter pipe carries water under a pressure (P,= 196.2 kPa.) with a Velocity of (V1= 3.5…
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Q: Consider a 150-mm-long segment of a simply supported beam. The internal bending moments on the left…
A: Given: To Find - Determine the maximum horizontal shear stress in this segment of the beam.
Q: The internal shear force V at a certain section of a steel beam is 80 kN, and the moment of inertia…
A: Horizontal shear stress. at point H. V = shear force = 80 KN or 80000 N I = 64,867,500 mm4
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- Find the resultant of two forces 130N and 110N respectively. acting at an angle whose tangent is 12/51.Curved beam ABC,AB=parabolic curve and BC is straight horizontal direction.Point B is the top of the curvature of the block with a slope of 0^o.Horizontal distance AB=6m;BC=2m and vertical distance AB=2m.The load is evenly distributed q works from A to E; the moment coupling load M and the concentrated load P with a slope of tan = 0.75 act at point C. The equation for the curvature of the parabolic beam AB is y=a+bx+cx^2. Questiona) Determine the equation of the parabolic curved cuboid ABb) Calculate all support reactions and indicate their direction(a) Draw the shear and moment curves for theframe in Figure P5.40. Sketch the deflected shape.(b) Write the equations for shear and moment in columnAB. Take the origin at A. (c) Write the shear and momentequations for girder BC. Take the origin at joint B.
- If mu = 0.30 under both blocks and A weighs 400 lb, find the maximum weight of B that can be started up the incline by applying to A a rightward force P of 500 lb.The horizontal shaft AD is attached to a fixed base at D and is subjected to the torques shown. A 44-mm-diameter hole has been drilled into portion CD of the shaft. The entire shaft is made of steel for which G = 77 GPa. 4. Calculate the angle of twist of point A relative to point D in degrees.A force F = (0.5i – 2.0j + 7.0k) kN acting at A(5, -4, 0)m about axis BC where B(6, 8, 4)m and C(-6, -5, 8)m. What is the perpendicular distance between F and the axis BC in meters?
- What is the general moment equation? Section the beam at the rightmost segment of the beam. El = 75,000 kN∙m23.) For the given couple-force system shown, determine the horizontal component of Q. P= 335 KN Q= 44 KN R=74 KN-m Z=263 KNA 50 N force, 188.9° relative to positive x-axis counterclockwise. Find the Fx and Fy components.