31. Tangent Lines (a) If f(x) = x – 2x + 4, find f'(a). (b) Find equations of the tangent lines to the graph of f at the points whose x-coordinates are 0, 1, and 2. (c) Graph f and the three tangent lines.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
icon
Related questions
Question
31. Tangent Lines
(a) If f(x) = x – 2x + 4, find f'(a).
(b) Find equations of the tangent lines to the graph of
f at the points whose x-coordinates are 0, 1, and 2.
(c) Graph f and the three tangent lines.
Transcribed Image Text:31. Tangent Lines (a) If f(x) = x – 2x + 4, find f'(a). (b) Find equations of the tangent lines to the graph of f at the points whose x-coordinates are 0, 1, and 2. (c) Graph f and the three tangent lines.
Expert Solution
Step 1

Solving:

a) Given:

                   f(x)=x3-2x+4

 

Take derivative of the given function with respect to x :

                 f'(x)=3x2-2

Now,

          Put x=a:

 Hence,

                 f'(a)=3a2-2

Step 2

Now,

            b) Equation of the tangent line at x-coordinates:

             Solution:

      Since:

                                f'(x)=3x2-2

       Put x=0:

                                 f'(0)=0-2        =-2

        And,

                               f(0)=0-0+4= 4f(0)=4

       Hence, The point is : (0, 4) and slope is -2

                            So, The equation of the tangent line is: 

                                                    y-y1=m(x-x1)y-4=-2(x-0)y-4=-2xy+2x=4 ........(1)

Hence, The equation of the tangent line at (0, 4) is : y+ 2x= 4  ......(1)

                      

Step 3

Now,

          Equation of the tangent line at x=1:

So,

           f(1)=1-2+4=3f(1)=3

Hence,

           To determine the equation of the tangent line at the point (1, 3):

So,

            Finding slope :

            f'(1)=3x2-2f'(1)=3-2= 1f'(1)=1

Hence,

                 The equation of the tangent line is: 

                                                    y-3=(x-1)y-3=(x-1)y-x=2            .......... (2)

 So, The equation of the tangent line at (1, 3) is : y-x= 2        ......(2)

                      

             

             

 

steps

Step by step

Solved in 5 steps with 1 images

Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781319050740
Author:
Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:
W. H. Freeman
Precalculus
Precalculus
Calculus
ISBN:
9780135189405
Author:
Michael Sullivan
Publisher:
PEARSON
Calculus: Early Transcendental Functions
Calculus: Early Transcendental Functions
Calculus
ISBN:
9781337552516
Author:
Ron Larson, Bruce H. Edwards
Publisher:
Cengage Learning