Question

Asked Oct 26, 2019

6 views

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped and has a mean of 53 and a standard deviation of 8. Using the empirical rule (as presented in the book), what is the approximate percentage of lightbulb replacement requests numbering between 37 and 53?

Do not enter the percent symbol.

ans = %

Step 1

**Solution: **We are given that the distribution of the number of daily requests is bell-shaped and has a mean of 53 and a standard deviation of 8.

Step 2

We are required to find the approximate percentage of lightbulb replacement requests numbering between 37 and 53.

Step 3

The empirical rule of the normal distribution states:

68% of data lies within one standard deviations of the mean

95% of data lies within two standard deviations of the mean

99.7% o...

Tagged in

Find answers to questions asked by student like you

Show more Q&A

Q: Grouping individuals into low, middle and high categories implies a scale of which type? Nominal O...

A: Levels of measurement:The variables can be classified based on the values that can be assigned to th...

Q: a manufacturer of bolts have a quality control policy that requires it to destroy any bolts that are...

A: It is given that the mean and standard deviation are 13 and 0.05, respectively.

Q: Determine the area under the standard normal curve that lies to the left of.. a) Z= 0.53 b) Z= -1.19...

A: a.The area under the standard normal curve that lies to the left of Z= 0.53 can be obtained using th...

Q: Will you show me step by step how to answer this, please?

A: Given DataP(X) = X + 0.2For X = 0.07P(X = 0.07) = 0.07 + 0.2 = 0.27For X = 0.16P(X = 0.16) = 0.16 + ...

Q: Consider a binominal experiment with 2 trials, and p=0.4 a. Compute the probability of 1 success, f(...

A: It is given that n = 2 and p = 0.4. Therefore, q = 1–p = 0.6.The PMF of binomial distribution is giv...

Q: A survery revealed the amount of pocket money held by each student in a sample of students. The amou...

A: Solution:The margin of error is obtained below:From the given information, number of observations is...

Q: What would the 95% confidence limits for a sample of 120 with a mean of 51 and a standard deviation ...

A: We are given:

Q: Sixty-eight percent of adults would still consider a car brand despite product/safety recalls. You r...

A: Given datap = 0.68n = 20The given distribution is Binomial distribution, because there are two outco...

Q: The number of chocolate chips in an 18-ounce bag of chocolate chip cookies is approximately normall...

A: Note:Hey, since there are multiple sub-parts question posted, we will answer first three sub-parts a...