Question
Asked Nov 8, 2019

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3r6
7. Let f(r
T-2
(a) Find f(-1), f(4)2 + 25(3) f(1)-3, f(z +2)
(b) Find zeros of f (x)
(c) Find the solutions to f(r
1-r = 1
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3r6 7. Let f(r T-2 (a) Find f(-1), f(4)2 + 25(3) f(1)-3, f(z +2) (b) Find zeros of f (x) (c) Find the solutions to f(r 1-r = 1

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check_circleExpert Solution
Step 1

The function is f(x) = (3x + 6) / (x – 2).

(a)

Obtain the values of f(-1),/(4)+2f(3) f (1)-3, f(z+2)
as follows.
3(-1) 6
=-1
f(-1)
(-1)+2
3(4)+6
42
3(3)6 3(1)6
+2
f(4)2(3)(1)3=
-3
(1)2
(3)+2
=-192
3(z+2)+6
(z+2)+2
f(z+2)=
3z 12
Z+4
help_outline

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Obtain the values of f(-1),/(4)+2f(3) f (1)-3, f(z+2) as follows. 3(-1) 6 =-1 f(-1) (-1)+2 3(4)+6 42 3(3)6 3(1)6 +2 f(4)2(3)(1)3= -3 (1)2 (3)+2 =-192 3(z+2)+6 (z+2)+2 f(z+2)= 3z 12 Z+4

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Step 2

(b)

Obtain the zeros of f(x) as...

Зх +6
0 =
х — 2
3x6 0
x 2
Therefore, the zeros of the function x = 2
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Зх +6 0 = х — 2 3x6 0 x 2 Therefore, the zeros of the function x = 2

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