3X ф.200 EQL SP F. G. 2X 0.220 Ф3.38 ВC R1.70 K. 6.56 2X R.30- N. 3.63 Ø3.000 $2,560 (н L) 20X R.15 R(C .30 TYP- 4X R.35 1.62- 4X 0.250 DR NOTE PART SYM ABOUT Y EXCEPT AS SHOWN UNSPECIFIED TOLERANCESI MATERIAL I 12-PL DEC IN.Cx.xx)±,01 250 BRASS DWN BY THIRD ANGLE PROJECTION D.E. LORENZ 3-PL DEC IN(x.xxx)±,005 REDRAVN BY M." ŽOKVIC SCALE CHKD LS 112 TITLE DRILLED HOLES 010 ADAPTER ANGLE ±0° 30' DWG NO. 11A005 46 LUnit E,

3X ф.200 EQL SP F. G. 2X 0.220 Ф3.38 ВC R1.70 K. 6.56 2X R.30- N. 3.63 Ø3.000 $2,560 (н L) 20X R.15 R(C .30 TYP- 4X R.35 1.62- 4X 0.250 DR NOTE PART SYM ABOUT Y EXCEPT AS SHOWN UNSPECIFIED TOLERANCESI MATERIAL I 12-PL DEC IN.Cx.xx)±,01 250 BRASS DWN BY THIRD ANGLE PROJECTION D.E. LORENZ 3-PL DEC IN(x.xxx)±,005 REDRAVN BY M." ŽOKVIC SCALE CHKD LS 112 TITLE DRILLED HOLES 010 ADAPTER ANGLE ±0° 30' DWG NO. 11A005 46 LUnit E,

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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ᴡʜᴀᴛ ɪꜱ ᴛʜᴇ ʜᴇʟᴍʜᴏʟᴛᴢ ᴀʙꜱᴏʟᴜᴛᴇ ᴠɪꜱᴄᴏꜱɪᴛʏ ᴏꜰ ᴡᴀᴛᴇʀ ᴀᴛ 670°ʀ?ᴡʜᴀᴛ ɪꜱ ᴛʜᴇ ᴡᴇɪɢʜᴛ ɪɴ ʟʙꜰ ᴏꜰ ᴀ ʟɪQᴜɪᴅ ᴛʜᴀᴛ ʜᴀꜱ ᴀ ᴍᴀꜱꜱ ᴏꜰ 30ʟʙᴍ ᴏɴ ᴇᴀʀᴛʜ ᴡɪᴛʜ ɢ=32.174ꜰᴛ/ꜱ2? ᴡᴇɪɢʜᴛ ɪɴ ʟʙꜰ ɪꜰ ᴛʜᴇ ɢ=29ꜰᴛ/ꜱ2? I will give like thanks!
assume that F={5i+5j+15k}kN.
vout1 =3.33, vout2=3.33, compare between them with the Thevenin theorem?
P= 10KN
Answer- Po=2.551 bar T=279.9K C=204.689m/s A=.07m2 Po =1.90 kg/s3 m=27.16 kg/s
Brigde was designed for ten years , and during the first four years was designed to carry 10 millions cars and one hundred thousand lorries ,at second four years was designid to cary 15 millions cars and two hunderd cars and during last two years was disigned to cary Smillions cars and one hunderd cars. Each car has fatique life of 10° cycles and each lorry of 10° cycles . Determine the brigde fatique life
i. 10hp engine is equivalent to. Ans. 7.46 kW ii. 20 hp engine is equal to. Ans. 1522.45 kg-m/sec
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ANS :1.Qa = 325,400.40 WSF = 02.a. wt' = 6300.00 kwb. x'2 = 94% c. wt = 6720.00 kwd. T2 = 24.1e. T1 = 465f. s2' = 34.10 g. T2' = 24.1 h. Ne' = 93.75i. delta s =1.55 kj/sec K
An air-cooled condenser has an expected U value of 30 W/m2∙K based on the airside. The condenser is to transfer 60 kW with an airflow rate of 15 kg/s entering at 35°C. If the condensing temperature is to be 48°C, what is the required airside area in m2? Round your answer to 2 decimal places.
Given: FN = 52 MN = 100 SN = 75
Can tutor explained the questions from d,e,f more clear on the step and if possible can it do by using the formula I had learnt so far which is s = Rθ v = Rω at = Rα T=2pi x square root(L/g) fn= 1/2pi x square root (k/m)