3x2 + 3x - 1 dx. (x – 1)(x² + 2x + 2)

Q: 2X+3-=X 3X%=DX メー3

A: We will solve the given equation to find the value of x that satisfies the equation. First of all we…

Q: a-) I = c6 Vx²-9 dx 3 b-) S x In(x² + 1) dx

A: Note: Since you have asked multiple questions, we will solve the first question for you. If you want…

Q: x+2 17. find a)) +1)(x2+1) dx b) x-2 dx 3x +1

A:

Q: •2 1 -dx- J-3 (x + 7)(x² + 16)

A: Given integral is Apply partial fractions to break the denominator

Q: (4x3-6х) dx 3. S x*-3x²+2

A: ∫4x3-6xx4-3x2+2dx we know that∫f'(x)f(x)dx = ln|f(x)| +cf'(x) =4x3-6x , f(x)=x4-3x2+2

Q: 1. f4x-³ dx -3

A: Find the integral

Q: 2x+3 a) S; dx x2-3x+2

A: We integrate the following by using substitution rules and factories the denominator.

Q: 2. x+4x²+x-1 dx 1 3+ 2.

A: First simplify the integrand to get the simpler integrand.

Q: S2x3-4 x²-x-3 dx х2-2х-3

A: See the details solution in below

Q: 2x5 – x3 + x +1 -dx - x(x² + 1)²

A:

Q: √(x² + 1)(2x³ − 3) dx . -

A:

Q: x²-3x - 7 √ - (x² + x + 2)(2x − 1) dx

A: Given: I=∫x2-3x-7x2+x+22x-1dx   As we know that; ∫1ax+bdx=1alnax+b+C

Q: -12 3 dx 12-x

A:

Q: 2x3+2x2-2x-1 dx x2+x

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Q: x²-3x - 7 2 (x² + x + 2)(2x - 1) dx

A: Simplifying the given integrand: x2-3x-7(x2+x+2)(2x-1)=x2-3x-72(x2+x+2)x-12

Q: (2x³-9x²+2) dx from x = 6 to x = 11

A: Given: ∫2x3-9x2+2dx   from x=6 to x=11

Q: 2 d 3)[(3x2 – 4x +7)(5x³ – 9x)®] dx - -

A: Here we apply u.v rule of multiplication in derivative

Q: 3/2 (-2x + 4) dx J1/2 | 16.

A: Note: We are authorized to answer one question at a time, since you have not mentioned which…

Q: On the interval [-3, 3] (x², x) = / dx = 1 ||x²|| = dx II

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Q: 3x2-9x-34 1. S- dx x2-2x-24

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Q: 2x (x-a)² dx; a is constant

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Q: x* - 5x² + 2 -dx X - 3

A: Explanation: Given that,  ∫x4-5x2+2x-3dx

Q: 2x2 + 3x – 3 dx X - 9

A:

Q: 2x ²-11)dx x3+3x²-4

A: To evaluate the integral.

Q: √ 1 x²√2x-x² dx = x+¹√ √√2x-x² + c 3x²

A:

Q: 2x + 1 Evaluate dx x2 - 7x + 12

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Q: ODE d²y dx² 1 -|> X dy xp ㅅ X² 1

A: We have to identify the type of the given differential equation. For this, we have to rearrange the…

Q: 2х-3 dx. (b) Evaluate 3x²-15x+1

A: Since you have asked multiple question, as per our guidelines we are supposed to answer only one…

Q: x²-3x - 7 √(x² + x + 2) (2x - 1) dx

A:

Q: 2. x°ー×- 8x ー1 dx x²-3X -4 2

A: according to our guidelines we can answer only three subparts, or question and rest can be reposted.…

Q: x+2 a) f- =dx V2x-x² |xIn(x+1)dx b)

A: Given that  (a) ∫(x+2)/√(2x-x2) dx   (b) ∫x ln(x+1)dx Here we have to calculate the given integral.

Q: х-6 Use the Quotient Rule to evaluate and simplify dx 5x-4 d X-6 dx 5x-4

A: The equation is x-65x-4.

Q: x(3-5х) J - (3x-1)(х-1)* # 2) Evaluate: -dx-

A:

Q: x +3 b. dx x2 - 3х - 10 с. x³ In(x²)dx at LKnow Chart part 2

A:

Q: √(x + 3) dx √16-x²

A: Solution

Q: (x3-4) 2. S dx x3+2x2+2x

A: To evalaute: I=∫x3-4x3+2x2+2xdx=∫1-2x2+2x+4x3+2x2+2xdx=∫dx-∫2x2+2x+4x3+2x2+2xdx

Q: 3. -2x-4 dx x-3 6x 4. (x2-7):/

A: (3).   The given integral is: ∫x3-2x2-4x-3dx

Q: 4x3-3x+5 If 13x+5 dx , then f (0) = x²-2x x²-2x,

A: Given : ∫4x3-3x+5x2-2xdx=∫fx+13x+5x2-2xdx Objective is to find the fx and then value of fx at x=0

Q: 2x2-5z-1 -dx ? x²(x-1)

A:

Q: 16 / #(x²)dx if f(x)dx = 7. Find Enter the exact answer. xf (x² )dx = -4

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Q: 3x+5 Find S dx (Using substitution method). √3x-7

A: This question can be solved using the concept of integration by substitution.

Q: (x3-2x2+1)dx (x2-2x+5)2

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Q: dx 2. x2 – 6x + 13 -4 dx 3. (x – 2)3

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Q: x+3 k) S- dx x2+6x-11

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Q: -2 х 6. dx 1-x

A: Topic = Integration use ∫1xdx=lnx+Clnx⇒x is NOT defined for negative values of the independent…

Q: 2. 16-x dx 2.

A:

Q: (х2-2х+11)dx (x2+3х-4) .2.

A:

Q: X 2 dx = V4-x2

A: I=∫01x24-x2dx =∫01(4-x2)+44-x2dx =∫014-x24-x2dx+∫0144-x2dx =∫014-x2dx+4∫0114-x2dx Here  ⇒∫a2-x2…