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(3x+4)^1\2=2x-4

Question

(3x+4)^1\2=2x-4

 

check_circleAnswer
Step 1

solve the equation.

(3x + 4)7 = 2x -4
3x+4 (2x-4)
3x 4 4x216x+16
4x219x12 0
4x2-19x12 = 0
4x2 -16x-3x 12 = 0
4x(x-4)-3x-4)0
(4x-3)(x-4) 0
3
and x 4
4
help_outline

Image Transcriptionclose

(3x + 4)7 = 2x -4 3x+4 (2x-4) 3x 4 4x216x+16 4x219x12 0 4x2-19x12 = 0 4x2 -16x-3x 12 = 0 4x(x-4)-3x-4)0 (4x-3)(x-4) 0 3 and x 4 4

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Step 2

Check the roots are solution o...

3
Substitute x- in (3x+ 4)2 = 2x-4,
4
(
4 2
3
4
4
4
9
+4
4
25
5
5
5
(False
2
2
Substitute x4 in (3.x+ 4)2 = 2x-4
1 7
(3(4)+4)2(4)-4
(12 4)8-4
(16)3 4
(True)
4 4
help_outline

Image Transcriptionclose

3 Substitute x- in (3x+ 4)2 = 2x-4, 4 ( 4 2 3 4 4 4 9 +4 4 25 5 5 5 (False 2 2 Substitute x4 in (3.x+ 4)2 = 2x-4 1 7 (3(4)+4)2(4)-4 (12 4)8-4 (16)3 4 (True) 4 4

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Math

Algebra

Equations and In-equations

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