Question
Asked Sep 26, 2019
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(3x-5)2+7(3x-5)+12=0

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Expert Answer

Step 1

Consider the given equation

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(3x-57(3x-5)+12 = 0 2

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Step 2

Let the substitute 3x-5=t  in the equation

then

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Step 3

Now solve the above ...

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27t12 0 2 t4t3t12 0 (+4)+3(+4)0 (1+4) (+3) 0

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Tagged in

Math

Algebra

Equations and In-equations