tan -1 tan

Q: tan x

A: Given y = tan x1 + tan x

Q: tan (180° - 0) = -tan(0).

A:

Q: 2. у %3D tan-1

A:

Q: a) Tan 36° b) Csc-23°

A: Given, a) tan(36o) using calculator value of tan(36o) is tan(36o) = 0.7265

Q: Sin13 T

A:

Q: 5T sin 7 sin

A:

Q: tan(-1)X- cot (-1)() = ? %3D

A:

Q: tan2 θ- sec2 θ =_________

A: To evaluate: tan2θ-sec2θ Solution: We have an identity: sec2θ-tan2θ=1 Therefore,…

Q: sec (tan-!1+ csc- 1)

A: Givensec(tan-11+csc-11)

Q: V3 tan 30 = - 1

A: tan π/6 = 1/3

Q: Sin 30°

A:

Q: simplify. 2 tan 15° / 1 − tan2 15°

A: We know the formula,  Tan(A+B) = (tanA + tanB)/(1-tanAtanB) Replacing B with A, Tan2A =…

Q: 1. у" + у %3 tanx

A: As per our guidelines, we can answer only first question, kindly repost the rest Solving the…

Q: . tan-1 (- 1) =_____________

A: Given expression: tan-1-1 Consider the value of tan-1-1=x Then, tanx=-1

Q: sin( 2 tan-1 (x/ 12)) = Select one:

A: Can solve the given function by using double angle formula

Q: 8 tan x = 24 tan x

A:

Q: tan X 35 Y X- 12 37

A: The length of a side XY=35 units. The length of a side YZ=12 units. The length of a side XZ=37…

Q: tan² 0 – sec² e :

A:

Q: tan(-0) sec(-0)

A: " Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: CSCX tan X CSCX

A:

Q: tan –1 [tan(-)] 6

A: Th expression is given as- tan-1tan-7π6 where θ=7π6 Since, θ lies in IIIrd quadrant, hence it should…

Q: an^-1(tan(4))

A: Giventan-1(tan(4))

Q: tan2θ - sec2 θ =..............

A: The trigonometric identity is given by: sec2θ=1+tan2θ

Q: sin(2 tan " (-} ))

A: Given,  sin2tan−1−83Formula→2tan−1x=sin−12xx2+1                 sinsin−1x=x

Q: tan 3.

A: Value of tan2π3=-3

Q: Tan(20)-tan0=0

A: see 2nd step.

Q: Tan(sin-1(-1/4))=

A: Consider the given expression:

Q: tan² x = tan x

A: tan2x=tanx

Q: Evaluate tan-'x dr

A: The given integral is  ∫-∞∞ tan-1x dx

Q: tan(0.2x - π)= -9

A:

Q: tan :- 1 6. I3I

A: We take tan inverse on both sides

Q: Simplify the expression. tan -2a-tan -3 1+tan –2æ tan –3æ tan x tan -4x tan -5x tan -3x

A: tanA-B = tanA-tan(B)1+tan(A)tan(B).

Q: tan @ 240

A:

Q: Sin(sin-1(4/7))=

A: Given information:

Q: sin(-645)

A:

Q: sin (e3") dr .

A:

Q: tan x = 1/7

A:

Q: Tanb =-2/5 & sinb<0

A:

Q: alcu

A: We have, x=180-100=80y=x=80z=y=80 Therefore we get, x+y+z°=80+80+80°=240° Hence the answer.

Q: Ctanx-tan3x tan3x find 1-Ctan2r

A:

Q: Evaluate sin -1  (1/2)

A:

Q: Sin13*

A:

Q: Find the exact value.

A: Given: a.tan330°b.tan-225°

Q: tan( -x) csc x

A:

Q: 6 - 6 tan (x+3)= -12

A:

Q: 15 tan3(x) = 5 tan(x) %3D

A:

Q: tan12/1-tan^2 12 simplify

A: Simplify tan121-tan212

Q: Sin0

A: Find the value of sin0

Q: tan x -1 X 1+ x?

A:

Fundamentals of Trigonometric Identities

Trigonometric Identities are the equalities that involve trigonometry functions and hold for all the values of variables given in the equation.