Question
Asked Oct 10, 2019
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4) The position of an
time in seconds the object has been in motion. How long (to the nearest tenth) will it take the object to
= 2t2- 3t, where s is in meters and t is the
object moving in a straight line is given by s
move 14 meters?
302
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4) The position of an time in seconds the object has been in motion. How long (to the nearest tenth) will it take the object to = 2t2- 3t, where s is in meters and t is the object moving in a straight line is given by s move 14 meters? 302

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Expert Answer

Step 1

Given s=14 meters , we have to find t=? 

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s=2t 2-3t 14-2t2-3t

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Step 2

Subtract 14 from both sides.

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14=2t 2-3t 0-2t2-3t-14

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Step 3

Use quadratic formula to f...

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2t 2-3t-14-0 3+ V(-3)-4(2)(-14) t= 2(2) 3+9+112 4 3+ V121

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