4 Vtot 21- the equivalent capacitance (Ceq)? ic 9F+3F=RF (1ZF)(UF) 3F=Cs Q,z=Q,=36 V tot 9 こLV What is the equivalent capacitance (Ceq)? Sp=C,+jc 9F+3F=12F CPC3 CP+C3 3F=C0 (IZF)(UF) (12F)+U(F) %3D What is the charge (qı) on capacitor 1 (C1)? 366 3(12)= 362 C=ev%3DQ ev=Q AV What is the charge (q2) on capacitor 2 (C2)? Qモこ QgVeごの(3:27C What is the charge (q3) on capacitor 3 (C3)? 9C C3V3= 3(3)=9c az= 36.C What is the total charge (qtot)? スot こひitata3 What is the voltage drop (V1) across C1? av. 36 こ9W Ci What is the voltage drop (V2) across C2? 3V Vz=/3V 2. What is the voltage drop (V3) across C3? 3V 3V 3. February 4, 20 Dr Swanson, Sandhills CC

Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter25: Capacitance And Dielectrics
Section: Chapter Questions
Problem 13P: Find the equivalent capacitance between points a and b in the combination of capacitors shown in...
icon
Related questions
Question

Can you look over my work and make sure I did the capacitors, voltage drop, and total charge correctly. Capacitor 1 is 4 f, capacitor 2 is 9 f, and capacitor 3 is 3 f. Also total voltage should be equal to 12 v. Therefore I think I'm doing something wrong here 

4
Vtot
21-
the equivalent capacitance (Ceq)?
ic 9F+3F=RF
(1ZF)(UF)
3F=Cs
Transcribed Image Text:4 Vtot 21- the equivalent capacitance (Ceq)? ic 9F+3F=RF (1ZF)(UF) 3F=Cs
Q,z=Q,=36
V tot
9
こLV
What is the equivalent capacitance (Ceq)?
Sp=C,+jc 9F+3F=12F
CPC3
CP+C3
3F=C0
(IZF)(UF)
(12F)+U(F)
%3D
What is the charge (qı) on capacitor 1 (C1)?
366
3(12)= 362
C=ev%3DQ
ev=Q
AV
What is the charge (q2) on capacitor 2 (C2)?
Qモこ QgVeごの(3:27C
What is the charge (q3) on capacitor 3 (C3)?
9C
C3V3= 3(3)=9c
az=
36.C
What is the total charge (qtot)?
スot こひitata3
What is the voltage drop (V1) across C1?
av.
36
こ9W
Ci
What is the voltage drop (V2) across C2?
3V
Vz=/3V
2.
What is the voltage drop (V3) across C3?
3V
3V
3.
February 4, 20
Dr Swanson, Sandhills CC
Transcribed Image Text:Q,z=Q,=36 V tot 9 こLV What is the equivalent capacitance (Ceq)? Sp=C,+jc 9F+3F=12F CPC3 CP+C3 3F=C0 (IZF)(UF) (12F)+U(F) %3D What is the charge (qı) on capacitor 1 (C1)? 366 3(12)= 362 C=ev%3DQ ev=Q AV What is the charge (q2) on capacitor 2 (C2)? Qモこ QgVeごの(3:27C What is the charge (q3) on capacitor 3 (C3)? 9C C3V3= 3(3)=9c az= 36.C What is the total charge (qtot)? スot こひitata3 What is the voltage drop (V1) across C1? av. 36 こ9W Ci What is the voltage drop (V2) across C2? 3V Vz=/3V 2. What is the voltage drop (V3) across C3? 3V 3V 3. February 4, 20 Dr Swanson, Sandhills CC
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 7 images

Blurred answer
Knowledge Booster
Electric field
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Physics for Scientists and Engineers with Modern …
Physics for Scientists and Engineers with Modern …
Physics
ISBN:
9781337553292
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Glencoe Physics: Principles and Problems, Student…
Glencoe Physics: Principles and Problems, Student…
Physics
ISBN:
9780078807213
Author:
Paul W. Zitzewitz
Publisher:
Glencoe/McGraw-Hill
University Physics Volume 2
University Physics Volume 2
Physics
ISBN:
9781938168161
Author:
OpenStax
Publisher:
OpenStax
Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
Physics
ISBN:
9781133104261
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Physics for Scientists and Engineers: Foundations…
Physics for Scientists and Engineers: Foundations…
Physics
ISBN:
9781133939146
Author:
Katz, Debora M.
Publisher:
Cengage Learning
College Physics
College Physics
Physics
ISBN:
9781938168000
Author:
Paul Peter Urone, Roger Hinrichs
Publisher:
OpenStax College