# 4. A 15 g piece of iron [cp = 25.09 J/(mol * °C)] is heated to a temperature of 100°C and placed into a bucket containing 1.0 L of water [cp = 75.38 J/(mol * °C)] at 25°C. What is the final temperature of the piece of iron and the water.

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4. A 15 g piece of iron [cp = 25.09 J/(mol * °C)] is heated to a temperature of 100°C and placed into a bucket containing 1.0 L of water [cp = 75.38 J/(mol * °C)] at 25°C. What is the final temperature of the piece of iron and the water.

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Step 1

The concept behind this question is the heat released by the metal is absorbed by the water. This can be represented by an equation as given below.

Step 2

The negative sign is indicating that the heat is released. The specific heat capacity is given in the unit of J/mol 0C, so mass should be converted into moles.

The calculation of moles are given below.

Step 3

Suppose, the final temperature for both iron and water is T. Then, by plugging all the val...

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