# 4. A student added 25.00 grams of sodium nitrate to a 2.00 Litre volumetric flask. Whatis the molarity (M) of the resulting solution?5. A student mixed 20.00 grams of calcium nitrate, 10.00 grams of sodium nitrate, and50.00 grams of aluminum nitrate in a 5.00 Litre volumetric flask. What is the molarity(M) of the resulting solution relative to the nitrate ion, NO31-?6. How many grams of phosphoric acid are required to react with 50.00 mL of a 0.800M calcium nitrate solution?

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Question 4 help_outlineImage Transcriptionclose4. A student added 25.00 grams of sodium nitrate to a 2.00 Litre volumetric flask. What is the molarity (M) of the resulting solution? 5. A student mixed 20.00 grams of calcium nitrate, 10.00 grams of sodium nitrate, and 50.00 grams of aluminum nitrate in a 5.00 Litre volumetric flask. What is the molarity (M) of the resulting solution relative to the nitrate ion, NO31-? 6. How many grams of phosphoric acid are required to react with 50.00 mL of a 0.800 M calcium nitrate solution? fullscreen
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Step 1

Solution stoichiometry involves the calculation of concentration of solutions in the given conditions of volumes, moles etc.

Step 2

Solution stoichiometry is mainly based on the calculation of moles and volumes. These two values are used to calculate the molarity of solution. The relation between moles, volume and molarity is as given below; help_outlineImage TranscriptioncloseMoles of solute Molarity volume of solution in L Mass of solute ing Moles Molar mass of solute (g/mol) fullscreen
Step 3

Mass of sodium nitrate = 25.00 g

Molar mass of sodium nitrate = ... help_outlineImage TranscriptioncloseMass (g) Moles of sodium nitrate = Molar mass (g/mol) 25.00 g Moles of sodium nitrate = | 84.99 g/mol Moles of sodium nitrate 0.2941 moles fullscreen

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