Math

ProbabilityQ&A Library4.ZF1110fleae Cunglatly to ttStandandNsmelNumPause8Len atandand maCune uhdt Ahis aDaa+750EndIns9750SO0019041 Remembn to pultraclYongtae asond halcadend in tableOdds o CengmirddeLotn deaimal andpeacent Cod Knows nnd teltALATuergi15 4;15wed 1;00-40OThu 154SassThe Cumulative Standardized Normal Distribution (continued)Entry represents area under the cumulative standardizednormal distribution from -0o to Z0 ZCumulative ProbabilitiesZ0.000.010.020.090.030.080.040.050.060.070.50000.00.50400.50800.53590.53190.51200.51600.52790.51990.52390.10.53980.54380.54780.57530.57140.55170.56750.55570.55960.56360.20.57930.58320.61410.58710.61030.60640.59100.59480.59870.60260.30.61790.62170.62550.66280.65170.64800.62930.64430.64060.63310.63680.40.65540.65910.68790.68440.66640.68080.67000.67720.67360.69150.50.69500.71900.69850.72240.70190.70540.71570.70880.71230.60.72570.72910.73240.75490.73570.73890.75180.74860.74220.74540.70.75800.76120.78520.76420.78230.76730.77040.77340.77640.7794.0.80.78810.79100.79390.81330.81060.79670.79950.80230.80510.80780.90.81590.81860.82120.83890.82380.82640.83650.83400.82890.83151.00.84130.84380.84610.86210.85080.85990.84850.85540.85770.85310.86651.10.86430.86860.87290.87080.87490.87900.88100.88300.87700.89250.88691.20.88490.88880.89070.8962O.89800.91470.89970.89440.90150.91151.30.90660.90320.90490.90820.90990.91620.91310.91770.92071.40.92220.92360.92510.91920.92650.92790.92920.93060.93190.93820.93700.93940.93450.93570.94061.50.93320.94180.94290.94410.94840.94950.94630.94740.95050.95150.95251.60.94520.95350.95450.95910.95820.95990.95730.96160.95640.96080.96251.70.95540.96330.96640.96780.96710.96560.96860.96930.96410.96490.96991.80.97060.97320.97260.97380.97440.97500.97190.97560.97610.97131.90.97670.97980.9788o30.97930.98030.97830.98080.97780.98120.97722.00.98170.98300.98340.98380.98420.98460.98260.98500.98540.98212.10.98570.98710.98750.98780.98810.98680.98640.98840.98870.98612.20.98900.99040.99060.98980.99010.99090.98960.99110.98930.99132.30.99160.99270.99290.99220.99250.99310.99320.99200.99180.99340.99362.40.99410.99450.99460.99430.99480.99490.99400.99380.99510.99522.50.99610.99600.99590.99560.99570.99620.99550.99530.99632.60.99640.99690.99700.99680.99670.99710.99720.99660.99650.99732.70.99740.99770.99770.99780.99760.99790.99750.99790.99740.99802.80.99810.99840.99830.99840.99820.99850.99820.99850.99810.99862.90.99860.998740.998780.998820.998860.998890.998690.998650.998930.998970.999003.00.999160.999100.999130.999180.999060.999210.999030.999240.999263.10.999290.999380.999360.999400.999420.999440.999340.999310.999460.999483.20.999500.999550.999600.999720.999570.999580.999610.999520.999530.999623.30.999640.999650.999700.999690.999710.999680.999660.999730.999810.999743.40.999750.999760.999790.999780.999800.999810.999780.999770.999823.50.999830.999830.999860.999850.999860.999870.999850.999870.999840.999883.60.999880.999890.999900.999910.999900.999910.999890.999900.999923.70.999920.999920.999920.999930.999940.999940.999940.999930.999930.999943.80.999950.999950.999950.999960.999960.999960.999950.999950.999960.999963.90.999960.999970.999970.9999683294.0Nagative.lSubhacr0.9999966024.5Flip0.9999997135.00.9999999810, 9905.50.9999999996.0./0a0 0.2990dont pantQuestion

Asked Oct 22, 2019

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Can I have this completed problem explained step by step it is complete but I need more info as to how to do it or how it was done on my paper using my chart as well

Step 1

**Note:**

Hey there! Thank you for the question. It was a little difficult for us to understand the question from the way it is written. We have identified the following two questions and solved them for you:

- In the standard normal curve, what is this area? (The shaded area in the first curve, the shading being between the values 0 and 1.96)
- Find, in the
*z*-table, the odds of being the middle 50%, both in decimal and in percent.

Whatever else is written in the paper, seems to be instructions as how to solve the problem.

We have used your graph, and re-drawn it, to make the image clearer for you to understand. You can compare and see that it is the same graph.

Step 2

**Question 1:**

In the second image of the standard normal table, the cumulative probability corresponding to the different values of *Z* are given, that is, the probability, *P* (*Z* < *z*) values are given.

The probability needed for the shaded area is: *P* (0 < *Z* < 1.96).

This can be re-written as follows:

*P* (0 < *Z* < 1.96)

= *P* (*Z* < 1.96) – *P* (*Z* < 0).

Observe that you can write: 1.96 = 1.9 + 0.06.

Procedure for *P* (*Z* < 0):

In the table given in the image, from the very first column (column name *Z*), locate the value 0.0.

Along the row of 0.0, move to the right, till you are under the 1st column. Note that the 1st column is 0.00.

The probability value in this cell is 0.5000, that is, *P* (*Z* < 0) = 0.5.

Procedure for *P* (*Z* < 1.96):

In the table given in the image, from the very first column (column name *...*

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