4.002.000.000200.400.600.000.801.001.202.00-4.00time(s)Figure 2: Position vs. Time- Amara's OscillatorAmara hangs am = 0.05 kg mass on a spring. She starts the mass oscillating in the vertical direction and recordsposition versus time for the oscillator. A plot of these data is shown in Figure 2.(u) x

Question
Asked Nov 18, 2019
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Compute the maximum velocity, maximum acceleration, and the maximum force.

4.00
2.00
0.00
020
0.40
0.60
0.00
0.80
1.00
1.20
2.00
-4.00
time(s)
Figure 2: Position vs. Time- Amara's Oscillator
Amara hangs am = 0.05 kg mass on a spring. She starts the mass oscillating in the vertical direction and records
position versus time for the oscillator. A plot of these data is shown in Figure 2.
(u) x
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4.00 2.00 0.00 020 0.40 0.60 0.00 0.80 1.00 1.20 2.00 -4.00 time(s) Figure 2: Position vs. Time- Amara's Oscillator Amara hangs am = 0.05 kg mass on a spring. She starts the mass oscillating in the vertical direction and records position versus time for the oscillator. A plot of these data is shown in Figure 2. (u) x

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Expert Answer

Step 1

Given

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Time period of the oscillati on, T = (0.84s-0.16s) 0.68s 2T Angular frequency, - T 0.68s 9.24rad s

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Step 2

The maximum velocity is

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Aco max 10 m 3.5cm x (9.24rad s lcm -0.323m/s

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Step 3

The maximum accel...

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amaxAc 10 m (9.24rad -s lcm 3.5 cm - 2.99m/s2

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