4.00of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 70. g/mol, is burnedcompletely in excess oxygen, and the mass of the products carefully measured:productmass12.57 gcarbon dioxide5.15 gwateralbUse this information to find the molecular formula of X.ArCheckExplanationPrivecyTerms of Use2019 McGraw-Hill Education. All Rights Reserved.925 PM12/5/2019O Type here to searchhpBopg upendhomeinsprt scdeletef12f11f10f8f610numescbackspacelock&8{home%24%23

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Asked Dec 6, 2019
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4.00
of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 70. g/mol, is burned
completely in excess oxygen, and the mass of the products carefully measured:
product
mass
12.57 g
carbon dioxide
5.15 g
water
alb
Use this information to find the molecular formula of X.
Ar
Check
Explanation
Privecy
Terms of Use
2019 McGraw-Hill Education. All Rights Reserved.
925 PM
12/5/2019
O Type here to search
hp
Bo
pg up
end
home
ins
prt sc
delete
f12
f11
f10
f8
f6
10
num
esc
backspace
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&
8
{
home
%24
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4.00 of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 70. g/mol, is burned completely in excess oxygen, and the mass of the products carefully measured: product mass 12.57 g carbon dioxide 5.15 g water alb Use this information to find the molecular formula of X. Ar Check Explanation Privecy Terms of Use 2019 McGraw-Hill Education. All Rights Reserved. 925 PM 12/5/2019 O Type here to search hp Bo pg up end home ins prt sc delete f12 f11 f10 f8 f6 10 num esc backspace lock & 8 { home %24 %23

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Step 1
Step 2

Moles of CO2 and H2O are calculated as shown below,

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12.57g Mass Moles of CO, = 0.2856 mole Molar mass 44.01g/mol 5.15g Mass Moles of H,0= = 0.2859mole Molar mass 18.015 g/mol

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Step 3

Moles of C, H, and O atoms are c...

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Mass of C= (Moles)(Molar mass) =(0.2856mol) (12 g/mol)=3.43g Mass of H= (Moles)(Molarmass) =2 (0.2859 mol) (1g/mol) =0.57g Mass of O =Mass of compound – mass of C – mass of H = 4g -(3.43g)- (0.57g) = 0.0g

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