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4.29 Calculate each of the following quantities:(a) Volume (L) of 2.050 M copper(II) nitrate that must be dilutedwith water to prepare 750.0 mL of a 0.8543 M solution)Volume (L) of 1.63 M calcium chloride that must be diluted withwater to prepare 350. mL of a 2.86x10 M chloride ion solution(c) Final volume (L) of a 0.0700 M solution prepared by diluting18.0 mL of 0.155 M lithium carbonate with water

Question
4.29 Calculate each of the following quantities:
(a) Volume (L) of 2.050 M copper(II) nitrate that must be diluted
with water to prepare 750.0 mL of a 0.8543 M solution
)Volume (L) of 1.63 M calcium chloride that must be diluted with
water to prepare 350. mL of a 2.86x10 M chloride ion solution
(c) Final volume (L) of a 0.0700 M solution prepared by diluting
18.0 mL of 0.155 M lithium carbonate with water
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4.29 Calculate each of the following quantities: (a) Volume (L) of 2.050 M copper(II) nitrate that must be diluted with water to prepare 750.0 mL of a 0.8543 M solution )Volume (L) of 1.63 M calcium chloride that must be diluted with water to prepare 350. mL of a 2.86x10 M chloride ion solution (c) Final volume (L) of a 0.0700 M solution prepared by diluting 18.0 mL of 0.155 M lithium carbonate with water

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Step 1

Solution stoichiometry involves the calculation of concentration of solutions in the given conditions of volumes, moles etc.

 

Step 2

Solution stoichiometry is mainly based on the calculation of moles and volumes. These two values are used to calculate the molarity of solution. The relation between moles, volume and molarity is as given below;

Moles of solute
Molarity
volume of solution in L
Mass of solute in g
Moles
Molar mass of solute (g/mol)
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Moles of solute Molarity volume of solution in L Mass of solute in g Moles Molar mass of solute (g/mol)

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Step 3

To calculate the molarity or volume of solution after dilution;...

М, xV, — М, х V,
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М, xV, — М, х V,

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