4.53. Heat-Transfer Area and Use of Log Mean Temperature Difference. A reaction mix-ture having a cpmfrom 377.6 K to 344,3 K. Cooling water at 288.8 K is available and the flow rate is4536 kg/h. The overall U, is 653 W/m2.K(a) For counterflow, calculate the outlet water temperature and the areathe exchanger.(b) Repeat for cocurrent flow.= 2.85 kJ/kg-K is flowing at a rate of 7260 kg/h and is to be cooled13.2-9Ao ofAns. (a) T 325.2 K, A5.43 m2 (b) A6.46 m2

Question
Step 1

Specific heat of reaction mixture cpm = 2.85 kJ/kg.K

Mass flow rate of reaction mixture mh = 7260 kg/h = 2.0167 kg/s

Initial temperature of the mixture Th1= 377.6 K

Final temperature of the mixture after cooling Th2 = 344.3 K

Temperature of the cooling water Tc1= 288.8 K

Mass flow rate of the cooling water mc = 4536 kg/h = 1.26 kg/s

The value of overall heat transfer coefficient Uo = 653 W/m2K

Step 2

The outlet water temperature and area Ao of the heat exchanger for counter flow can be calculated as follows.

Step 3

The value of LMTD (Log Mean Temperature ...

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