#43 in 1.8 of precalculus mathematics for calculus 7th edition Solve the nonlinear inequality and show the solution in interval notation. 2X2 +x (> or equal to) 1 2x2 +x -1 (> or equal to) 0 (X-0.5)(x+1) (>or equal to) 0 It says in the book that 0.5 (<or equal to) x (<or equal to) -1 However I got that x (>or equal to) -1 And x (>or equal to) 0.5 But it's to my understanding that you only change the inequality sign when multiplying or dividing by a negative, which is not the case here, but somewhere the sign is supposed to flip when stating the relationship between x and -1. In bartleby solutions it uses a table to determine the signs of each interval, but I dont understand why it's being used, and the math seems to be incorrect in the last row.
#43 in 1.8 of precalculus mathematics for calculus 7th edition
Solve the nonlinear inequality and show the solution in interval notation.
2X2 +x (> or equal to) 1
2x2 +x -1 (> or equal to) 0
(X-0.5)(x+1) (>or equal to) 0
It says in the book that
0.5 (<or equal to) x (<or equal to) -1
However I got that x (>or equal to) -1
And x (>or equal to) 0.5
But it's to my understanding that you only change the inequality sign when multiplying or dividing by a negative, which is not the case here, but somewhere the sign is supposed to flip when stating the relationship between x and -1.
In bartleby solutions it uses a table to determine the signs of each interval, but I dont understand why it's being used, and the math seems to be incorrect in the last row.
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