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Social ScienceThe figure shows a rectangular array of charged particles fixed in place, with distance a = 33.7 cm and the charges shown as integer multiples of q1 = 3.32 pC and q2 = 7.25 pC. With V= 0 at infinity, what is the net electric potential at the rectangle's center?
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+442 +24 a +21 +442
Expert Answer
The distance between each charge, a = 33.7 cm = 0.337 m
Charges shown in the array are multiples of, q1=3.32 pC = 3.32 x 10-12C and , q2=7.25 pC= 7.25 x 10-12C
We need to find the electric potential at the center of the rectangular array.
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+42 +24 a/2 a/2 +21 +442
The electric potential due to charges arranged in the rectangular array can be calculated by finding the potential due to individual charges at the center and then adding them up.
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1 4TE -3q,+2 a 5a +442 + +2q,+4 a 1 + 5a + V 4 тE, 2 2 2 2 2 2 1 0+ 4q2 4q2 2q, - З4, + 29, —4 1 4TE Va 47TE 2 2 2
Substitute the ...
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4x7.25x102 c 4q2 3.14x8.85 x1012c'n'm2x0.168m 6.21V TE,а
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