44-46 Use the Theorem of Pappus to find the volume of the given solid. 44. A sphere of radius r (Use Example 4.) 1. EXAMPLE 4 Find the center of mass of a semicircular plate of radius r. yA y=Vr-x² SOLUTION In order to use (8) we place the semicircle as in Figure 11 so that f(x) = vr2 – x² and a = -r, b = r. Here there is no need to use the formula to cal- (o 4r) culate x because, by the symmetry principle, the center of mass must lie on the y-axis, 0, so x = 0. The area of the semicircle is A = Tr', so ỹ = ĀL,[S(x)]*dx bebaiua FIGURE 11 (W - x2)° dx .2 (- x*) dx (since the integrand is even) Tr Jo .3 TTr 3 01 EXERC 2 2r3 4r Tr? 3 Зт The center of mass is located at the point (0, 4r/(3T)).

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number 44 and it says use example 4 so i attached that as well

44-46 Use the Theorem of Pappus to find the volume of the
given solid.
44. A sphere of radius r (Use Example 4.)
1.
Transcribed Image Text:44-46 Use the Theorem of Pappus to find the volume of the given solid. 44. A sphere of radius r (Use Example 4.) 1.
EXAMPLE 4 Find the center of mass of a semicircular plate of radius r.
yA
y=Vr-x²
SOLUTION In order to use (8) we place the semicircle as in Figure 11 so that
f(x) = vr2 – x² and a = -r, b = r. Here there is no need to use the formula to cal-
(o 4r) culate x because, by the symmetry principle, the center of mass must lie on the y-axis,
0,
so x = 0. The area of the semicircle is A = Tr', so
ỹ =
ĀL,[S(x)]*dx
bebaiua
FIGURE 11
(W - x2)° dx
.2
(- x*) dx
(since the integrand is even)
Tr Jo
.3
TTr
3
01
EXERC
2 2r3
4r
Tr? 3
Зт
The center of mass is located at the point (0, 4r/(3T)).
Transcribed Image Text:EXAMPLE 4 Find the center of mass of a semicircular plate of radius r. yA y=Vr-x² SOLUTION In order to use (8) we place the semicircle as in Figure 11 so that f(x) = vr2 – x² and a = -r, b = r. Here there is no need to use the formula to cal- (o 4r) culate x because, by the symmetry principle, the center of mass must lie on the y-axis, 0, so x = 0. The area of the semicircle is A = Tr', so ỹ = ĀL,[S(x)]*dx bebaiua FIGURE 11 (W - x2)° dx .2 (- x*) dx (since the integrand is even) Tr Jo .3 TTr 3 01 EXERC 2 2r3 4r Tr? 3 Зт The center of mass is located at the point (0, 4r/(3T)).
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